leetcode-problemset/leetcode-cn/originData/number-of-arithmetic-triplets.json

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            "title": "Number of Arithmetic Triplets",
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            "content": "<p>You are given a <strong>0-indexed</strong>, <strong>strictly increasing</strong> integer array <code>nums</code> and a positive integer <code>diff</code>. A triplet <code>(i, j, k)</code> is an <strong>arithmetic triplet</strong> if the following conditions are met:</p>\n\n<ul>\n\t<li><code>i &lt; j &lt; k</code>,</li>\n\t<li><code>nums[j] - nums[i] == diff</code>, and</li>\n\t<li><code>nums[k] - nums[j] == diff</code>.</li>\n</ul>\n\n<p>Return <em>the number of unique <strong>arithmetic triplets</strong>.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,1,4,6,7,10], diff = 3\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\n(1, 2, 4) is an arithmetic triplet because both 7 - 4 == 3 and 4 - 1 == 3.\n(2, 4, 5) is an arithmetic triplet because both 10 - 7 == 3 and 7 - 4 == 3. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [4,5,6,7,8,9], diff = 2\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\n(0, 2, 4) is an arithmetic triplet because both 8 - 6 == 2 and 6 - 4 == 2.\n(1, 3, 5) is an arithmetic triplet because both 9 - 7 == 2 and 7 - 5 == 2.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= nums.length &lt;= 200</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 200</code></li>\n\t<li><code>1 &lt;= diff &lt;= 50</code></li>\n\t<li><code>nums</code> is <strong>strictly</strong> increasing.</li>\n</ul>\n",
            "translatedTitle": "等差三元组的数目",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始、<strong>严格递增</strong> 的整数数组 <code>nums</code> 和一个正整数 <code>diff</code> 。如果满足下述全部条件，则三元组 <code>(i, j, k)</code> 就是一个 <strong>等差三元组</strong> ：</p>\n\n<ul>\n\t<li><code>i &lt; j &lt; k</code> ，</li>\n\t<li><code>nums[j] - nums[i] == diff</code> 且</li>\n\t<li><code>nums[k] - nums[j] == diff</code></li>\n</ul>\n\n<p>返回不同 <strong>等差三元组</strong> 的数目<em>。</em></p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0,1,4,6,7,10], diff = 3\n<strong>输出：</strong>2\n<strong>解释：</strong>\n(1, 2, 4) 是等差三元组：7 - 4 == 3 且 4 - 1 == 3 。\n(2, 4, 5) 是等差三元组：10 - 7 == 3 且 7 - 4 == 3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [4,5,6,7,8,9], diff = 2\n<strong>输出：</strong>2\n<strong>解释：</strong>\n(0, 2, 4) 是等差三元组：8 - 6 == 2 且 6 - 4 == 2 。\n(1, 3, 5) 是等差三元组：9 - 7 == 2 且 7 - 5 == 2 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= nums.length &lt;= 200</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 200</code></li>\n\t<li><code>1 &lt;= diff &lt;= 50</code></li>\n\t<li><code>nums</code> <strong>严格</strong> 递增</li>\n</ul>\n",
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