leetcode-problemset/leetcode-cn/originData/minimum-processing-time.json

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        "question": {
            "questionId": "3151",
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            "categoryTitle": "Algorithms",
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            "title": "Minimum Processing Time",
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            "content": "<p>You have a certain number of processors, each having 4 cores. The number of tasks to be executed is four times the number of processors. Each task must be assigned to a unique core, and each core can only be used once.</p>\n\n<p>You are given an array <code>processorTime</code> representing the time each processor becomes available and an array <code>tasks</code> representing how long each task takes to complete. Return the&nbsp;<em>minimum</em> time needed to complete all tasks.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">processorTime = [8,10], tasks = [2,2,3,1,8,7,4,5]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">16</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Assign the tasks at indices 4, 5, 6, 7 to the first processor which becomes available at <code>time = 8</code>, and the tasks at indices 0, 1, 2, 3 to the second processor which becomes available at <code>time = 10</code>.&nbsp;</p>\n\n<p>The time taken by the first processor to finish the execution of all tasks is&nbsp;<code>max(8 + 8, 8 + 7, 8 + 4, 8 + 5) = 16</code>.</p>\n\n<p>The time taken by the second processor to finish the execution of all tasks is&nbsp;<code>max(10 + 2, 10 + 2, 10 + 3, 10 + 1) = 13</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">processorTime = [10,20], tasks = [2,3,1,2,5,8,4,3]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">23</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Assign the tasks at indices 1, 4, 5, 6 to the first processor and the others to the second processor.</p>\n\n<p>The time taken by the first processor to finish the execution of all tasks is <code>max(10 + 3, 10 + 5, 10 + 8, 10 + 4) = 18</code>.</p>\n\n<p>The time taken by the second processor to finish the execution of all tasks is <code>max(20 + 2, 20 + 1, 20 + 2, 20 + 3) = 23</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == processorTime.length &lt;= 25000</code></li>\n\t<li><code>1 &lt;= tasks.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= processorTime[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= tasks[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>tasks.length == 4 * n</code></li>\n</ul>\n",
            "translatedTitle": "最小处理时间",
            "translatedContent": "<p>你有 <code>n</code> 颗处理器，每颗处理器都有 <code>4</code> 个核心。现有 <code>n * 4</code> 个待执行任务，每个核心只执行 <strong>一次</strong>&nbsp;任务。</p>\n\n<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>processorTime</code> ，表示每颗处理器最早空闲时间。另给你一个下标从 <strong>0</strong> 开始的整数数组 <code>tasks</code> ，表示执行每个任务所需的时间。返回所有任务都执行完毕需要的 <strong>最小时间</strong> 。</p>\n\n<p>注意：每个核心独立执行任务。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>processorTime = [8,10], tasks = [2,2,3,1,8,7,4,5]\n<strong>输出：</strong>16\n<strong>解释：</strong>\n最优的方案是将下标为 4, 5, 6, 7 的任务分配给第一颗处理器（最早空闲时间 time = 8），下标为 0, 1, 2, 3 的任务分配给第二颗处理器（最早空闲时间 time = 10）。 \n第一颗处理器执行完所有任务需要花费的时间 = max(8 + 8, 8 + 7, 8 + 4, 8 + 5) = 16 。\n第二颗处理器执行完所有任务需要花费的时间 = max(10 + 2, 10 + 2, 10 + 3, 10 + 1) = 13 。\n因此，可以证明执行完所有任务需要花费的最小时间是 16 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>processorTime = [10,20], tasks = [2,3,1,2,5,8,4,3]\n<strong>输出：</strong>23\n<strong>解释：</strong>\n最优的方案是将下标为 1, 4, 5, 6 的任务分配给第一颗处理器（最早空闲时间 time = 10），下标为 0, 2, 3, 7 的任务分配给第二颗处理器（最早空闲时间 time = 20）。 \n第一颗处理器执行完所有任务需要花费的时间 = max(10 + 3, 10 + 5, 10 + 8, 10 + 4) = 18 。 \n第二颗处理器执行完所有任务需要花费的时间 = max(20 + 2, 20 + 1, 20 + 2, 20 + 3) = 23 。 \n因此，可以证明执行完所有任务需要花费的最小时间是 23 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == processorTime.length &lt;= 25000</code></li>\n\t<li><code>1 &lt;= tasks.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= processorTime[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= tasks[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>tasks.length == 4 * n</code></li>\n</ul>\n",
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