leetcode-problemset/leetcode-cn/originData/longest-unequal-adjacent-groups-subsequence-ii.json

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        "question": {
            "questionId": "3142",
            "questionFrontendId": "2901",
            "categoryTitle": "Algorithms",
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            "title": "Longest Unequal Adjacent Groups Subsequence II",
            "titleSlug": "longest-unequal-adjacent-groups-subsequence-ii",
            "content": "<p>You are given a string array <code>words</code>, and an array <code>groups</code>, both arrays having length <code>n</code>.</p>\n\n<p>The <strong>hamming distance</strong> between two strings of equal length is the number of positions at which the corresponding characters are <strong>different</strong>.</p>\n\n<p>You need to select the <strong>longest</strong> <span data-keyword=\"subsequence-array\">subsequence</span> from an array of indices <code>[0, 1, ..., n - 1]</code>, such that for the subsequence denoted as <code>[i<sub>0</sub>, i<sub>1</sub>, ..., i<sub>k-1</sub>]</code> having length <code>k</code>, the following holds:</p>\n\n<ul>\n\t<li>For <strong>adjacent</strong> indices in the subsequence, their corresponding groups are <strong>unequal</strong>, i.e., <code>groups[i<sub>j</sub>] != groups[i<sub>j+1</sub>]</code>, for each <code>j</code> where <code>0 &lt; j + 1 &lt; k</code>.</li>\n\t<li><code>words[i<sub>j</sub>]</code> and <code>words[i<sub>j+1</sub>]</code> are <strong>equal</strong> in length, and the <strong>hamming distance</strong> between them is <code>1</code>, where <code>0 &lt; j + 1 &lt; k</code>, for all indices in the subsequence.</li>\n</ul>\n\n<p>Return <em>a string array containing the words corresponding to the indices <strong>(in order)</strong> in the selected subsequence</em>. If there are multiple answers, return <em>any of them</em>.</p>\n\n<p><strong>Note:</strong> strings in <code>words</code> may be <strong>unequal</strong> in length.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\" style=\"border-color: var(--border-tertiary); border-left-width: 2px; color: var(--text-secondary); font-size: .875rem; margin-bottom: 1rem; margin-top: 1rem; overflow: visible; padding-left: 1rem;\">\n<p><strong>Input: </strong><span class=\"example-io\" style=\"font-family: Menlo,sans-serif; font-size: 0.85rem;\">words = [&quot;bab&quot;,&quot;dab&quot;,&quot;cab&quot;], groups = [1,2,2]</span></p>\n\n<p><strong>Output: </strong><span class=\"example-io\" style=\"font-family: Menlo,sans-serif; font-size: 0.85rem;\">[&quot;bab&quot;,&quot;cab&quot;]</span></p>\n\n<p><strong>Explanation: </strong>A subsequence that can be selected is <code>[0,2]</code>.</p>\n\n<ul>\n\t<li><code>groups[0] != groups[2]</code></li>\n\t<li><code>words[0].length == words[2].length</code>, and the hamming distance between them is 1.</li>\n</ul>\n\n<p>So, a valid answer is <code>[words[0],words[2]] = [&quot;bab&quot;,&quot;cab&quot;]</code>.</p>\n\n<p>Another subsequence that can be selected is <code>[0,1]</code>.</p>\n\n<ul>\n\t<li><code>groups[0] != groups[1]</code></li>\n\t<li><code>words[0].length == words[1].length</code>, and the hamming distance between them is <code>1</code>.</li>\n</ul>\n\n<p>So, another valid answer is <code>[words[0],words[1]] = [&quot;bab&quot;,&quot;dab&quot;]</code>.</p>\n\n<p>It can be shown that the length of the longest subsequence of indices that satisfies the conditions is <code>2</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\" style=\"border-color: var(--border-tertiary); border-left-width: 2px; color: var(--text-secondary); font-size: .875rem; margin-bottom: 1rem; margin-top: 1rem; overflow: visible; padding-left: 1rem;\">\n<p><strong>Input: </strong><span class=\"example-io\" style=\"font-family: Menlo,sans-serif; font-size: 0.85rem;\">words = [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;,&quot;d&quot;], groups = [1,2,3,4]</span></p>\n\n<p><strong>Output: </strong><span class=\"example-io\" style=\"font-family: Menlo,sans-serif; font-size: 0.85rem;\">[&quot;a&quot;,&quot;b&quot;,&quot;c&quot;,&quot;d&quot;]</span></p>\n\n<p><strong>Explanation: </strong>We can select the subsequence <code>[0,1,2,3]</code>.</p>\n\n<p>It satisfies both conditions.</p>\n\n<p>Hence, the answer is <code>[words[0],words[1],words[2],words[3]] = [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;,&quot;d&quot;]</code>.</p>\n\n<p>It has the longest length among all subsequences of indices that satisfy the conditions.</p>\n\n<p>Hence, it is the only answer.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == words.length == groups.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 10</code></li>\n\t<li><code>1 &lt;= groups[i] &lt;= n</code></li>\n\t<li><code>words</code> consists of <strong>distinct</strong> strings.</li>\n\t<li><code>words[i]</code> consists of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "最长相邻不相等子序列 II",
            "translatedContent": "<p>给你一个整数&nbsp;<code>n</code>&nbsp;和一个下标从&nbsp;<strong>0</strong>&nbsp;开始的字符串数组&nbsp;<code>words</code>&nbsp;，和一个下标从&nbsp;<strong>0</strong>&nbsp;开始的数组&nbsp;<code>groups</code>&nbsp;，两个数组长度都是&nbsp;<code>n</code>&nbsp;。</p>\n\n<p>两个长度相等字符串的 <strong>汉明距离</strong>&nbsp;定义为对应位置字符&nbsp;<strong>不同</strong>&nbsp;的数目。</p>\n\n<p>你需要从下标&nbsp;<code>[0, 1, ..., n - 1]</code>&nbsp;中选出一个&nbsp;<strong>最长<span data-keyword=\"subsequence-array\">子序列</span></strong>&nbsp;，将这个子序列记作长度为 <code>k</code> 的&nbsp;<code>[i<sub>0</sub>, i<sub>1</sub>, ..., i<sub>k - 1</sub>]</code>&nbsp;，它需要满足以下条件：</p>\n\n<ul>\n\t<li><strong>相邻</strong> 下标对应的 <code>groups</code> 值 <strong>不同</strong>。即，对于所有满足&nbsp;<code>0 &lt; j + 1 &lt; k</code>&nbsp;的&nbsp;<code>j</code>&nbsp;都有&nbsp;<code>groups[i<sub>j</sub>] != groups[i<sub>j + 1</sub>]</code>&nbsp;。</li>\n\t<li>对于所有&nbsp;<code>0 &lt; j + 1 &lt; k</code>&nbsp;的下标&nbsp;<code>j</code>&nbsp;，都满足&nbsp;<code>words[i<sub>j</sub>]</code> 和&nbsp;<code>words[i<sub>j + 1</sub>]</code>&nbsp;的长度 <strong>相等</strong>&nbsp;，且两个字符串之间的 <strong>汉明距离</strong>&nbsp;为 <code>1</code>&nbsp;。</li>\n</ul>\n\n<p>请你返回一个字符串数组，它是下标子序列&nbsp;<strong>依次</strong>&nbsp;对应&nbsp;<code>words</code>&nbsp;数组中的字符串连接形成的字符串数组。如果有多个答案，返回任意一个。</p>\n\n<p><strong>子序列</strong>&nbsp;指的是从原数组中删掉一些（也可能一个也不删掉）元素，剩余元素不改变相对位置得到的新的数组。</p>\n\n<p><b>注意：</b><code>words</code>&nbsp;中的字符串长度可能&nbsp;<strong>不相等</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>n = 3, words = [\"bab\",\"dab\",\"cab\"], groups = [1,2,2]\n<b>输出：</b>[\"bab\",\"cab\"]\n<b>解释：</b>一个可行的子序列是 [0,2] 。\n- groups[0] != groups[2]\n- words[0].length == words[2].length 且它们之间的汉明距离为 1 。\n所以一个可行的答案是 [words[0],words[2]] = [\"bab\",\"cab\"] 。\n另一个可行的子序列是 [0,1] 。\n- groups[0] != groups[1]\n- words[0].length = words[1].length 且它们之间的汉明距离为 1 。\n所以另一个可行的答案是 [words[0],words[1]] = [\"bab\",\"dab\"] 。\n符合题意的最长子序列的长度为 2 。</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>n = 4, words = [\"a\",\"b\",\"c\",\"d\"], groups = [1,2,3,4]\n<b>输出：</b>[\"a\",\"b\",\"c\",\"d\"]\n<b>解释：</b>我们选择子序列 [0,1,2,3] 。\n它同时满足两个条件。\n所以答案为 [words[0],words[1],words[2],words[3]] = [\"a\",\"b\",\"c\",\"d\"] 。\n它是所有下标子序列里最长且满足所有条件的。\n所以它是唯一的答案。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><b>提示：</b></p>\n\n<ul>\n\t<li><code>1 &lt;= n == words.length == groups.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 10</code></li>\n\t<li><code>1 &lt;= groups[i] &lt;= n</code></li>\n\t<li><code>words</code>&nbsp;中的字符串&nbsp;<strong>互不相同</strong>&nbsp;。</li>\n\t<li><code>words[i]</code> 只包含小写英文字母。</li>\n</ul>\n",
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<code>use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/troydhanson.github.io\\/uthash\\/\\\" target=\\\"_blank\\\">uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n<p><b>1. \\u5f80\\u54c8\\u5e0c\\u8868\\u4e2d\\u6dfb\\u52a0\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n    int id;            \\/* we'll use this field as the key *\\/\\r\\n    char name[10];\\r\\n    UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry 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\\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.11<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u4f7f\\u7528\\u7684\\u662f JetBrains \\u63d0\\u4f9b\\u7684 experimental compiler\\u3002\\u5982\\u679c\\u60a8\\u8ba4\\u4e3a\\u60a8\\u9047\\u5230\\u4e86\\u7f16\\u8bd1\\u5668\\u76f8\\u5173\\u7684\\u95ee\\u9898\\uff0c\\u8bf7\\u5411\\u6211\\u4eec\\u53cd\\u9988<\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.79.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a> \\u548c <a href=\\\"https:\\/\\/crates.io\\/crates\\/regex\\\" target=\\\"_blank\\\">regex<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.1.6<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2022<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/priority-queue\\/blob\\/v5\\/README.md\\\" target=\\\"_blank\\\"> datastructures-js\\/priority-queue@5.4.0<\\/a>\\uff0c<a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\/tree\\/v4.2.3\\\" target=\\\"_blank\\\"> datastructures-js\\/queue@4.2.3<\\/a> \\u4ee5\\u53ca <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/deque\\/tree\\/v1.0.4\\\" target=\\\"_blank\\\"> datastructures-js\\/deque@1.0.4<\\/a>\\u3002<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.15<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 26\"],\"elixir\":[\"Elixir\",\"Elixir 1.17 with Erlang\\/OTP 26\"],\"dart\":[\"Dart\",\"<p>Dart 3.2\\u3002\\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/pub.dev\\/packages\\/collection\\/versions\\/1.18.0\\\" target=\\\"_blank\\\">collection<\\/a> \\u5305<\\/p>\\r\\n\\r\\n<p>\\u60a8\\u7684\\u4ee3\\u7801\\u5c06\\u4f1a\\u88ab\\u4e0d\\u7f16\\u8bd1\\u76f4\\u63a5\\u8fd0\\u884c<\\/p>\"],\"cangjie\":[\"Cangjie\",\"<p>\\u7248\\u672c\\uff1a0.53.11 (cjnative)<\\/p>\\r\\n\\r\\n<p>\\u7f16\\u8bd1\\u53c2\\u6570\\uff1a<code>-O2 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