leetcode-problemset/leetcode-cn/originData/longest-palindromic-substring.json

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            "title": "Longest Palindromic Substring",
            "titleSlug": "longest-palindromic-substring",
            "content": "<p>Given a string <code>s</code>, return <em>the longest</em> <span data-keyword=\"palindromic-string\"><em>palindromic</em></span> <span data-keyword=\"substring-nonempty\"><em>substring</em></span> in <code>s</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;babad&quot;\n<strong>Output:</strong> &quot;bab&quot;\n<strong>Explanation:</strong> &quot;aba&quot; is also a valid answer.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;cbbd&quot;\n<strong>Output:</strong> &quot;bb&quot;\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code> consist of only digits and English letters.</li>\n</ul>\n",
            "translatedTitle": "最长回文子串",
            "translatedContent": "<p>给你一个字符串 <code>s</code>，找到 <code>s</code> 中最长的 <span data-keyword=\"palindromic-string\">回文</span> <span data-keyword=\"substring-nonempty\">子串</span>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"babad\"\n<strong>输出：</strong>\"bab\"\n<strong>解释：</strong>\"aba\" 同样是符合题意的答案。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"cbbd\"\n<strong>输出：</strong>\"bb\"\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code> 仅由数字和英文字母组成</li>\n</ul>\n",
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            "hints": [
                "How can we reuse a previously computed palindrome to compute a larger palindrome?",
                "If “aba” is a palindrome, is “xabax” a palindrome? Similarly is “xabay” a palindrome?",
                "Complexity based hint:</br>\r\nIf we use brute-force and check whether for every start and end position a substring is a palindrome we have O(n^2) start - end pairs and O(n) palindromic checks. Can we reduce the time for palindromic checks to O(1) by reusing some previous computation."
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