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{
"data": {
"question": {
"questionId": "3495",
"questionFrontendId": "3275",
"categoryTitle": "Algorithms",
"boundTopicId": 2857597,
"title": "K-th Nearest Obstacle Queries",
"titleSlug": "k-th-nearest-obstacle-queries",
"content": "<p>There is an infinite 2D plane.</p>\n\n<p>You are given a positive integer <code>k</code>. You are also given a 2D array <code>queries</code>, which contains the following queries:</p>\n\n<ul>\n\t<li><code>queries[i] = [x, y]</code>: Build an obstacle at coordinate <code>(x, y)</code> in the plane. It is guaranteed that there is <strong>no</strong> obstacle at this coordinate when this query is made.</li>\n</ul>\n\n<p>After each query, you need to find the <strong>distance</strong> of the <code>k<sup>th</sup></code> <strong>nearest</strong> obstacle from the origin.</p>\n\n<p>Return an integer array <code>results</code> where <code>results[i]</code> denotes the <code>k<sup>th</sup></code> nearest obstacle after query <code>i</code>, or <code>results[i] == -1</code> if there are less than <code>k</code> obstacles.</p>\n\n<p><strong>Note</strong> that initially there are <strong>no</strong> obstacles anywhere.</p>\n\n<p>The <strong>distance</strong> of an obstacle at coordinate <code>(x, y)</code> from the origin is given by <code>|x| + |y|</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">queries = [[1,2],[3,4],[2,3],[-3,0]], k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[-1,7,5,3]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Initially, there are 0 obstacles.</li>\n\t<li>After <code>queries[0]</code>, there are less than 2 obstacles.</li>\n\t<li>After <code>queries[1]</code>, there are obstacles at distances 3 and 7.</li>\n\t<li>After <code>queries[2]</code>, there are obstacles at distances 3, 5, and 7.</li>\n\t<li>After <code>queries[3]</code>, there are obstacles at distances 3, 3, 5, and 7.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">queries = [[5,5],[4,4],[3,3]], k = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[10,8,6]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>After <code>queries[0]</code>, there is an obstacle at distance 10.</li>\n\t<li>After <code>queries[1]</code>, there are obstacles at distances 8 and 10.</li>\n\t<li>After <code>queries[2]</code>, there are obstacles at distances 6, 8, and 10.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= queries.length &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li>All <code>queries[i]</code> are unique.</li>\n\t<li><code>-10<sup>9</sup> &lt;= queries[i][0], queries[i][1] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
"translatedTitle": "第 K 近障碍物查询",
"translatedContent": "<p>有一个无限大的二维平面。</p>\n\n<p>给你一个正整数&nbsp;<code>k</code>&nbsp;,同时给你一个二维数组&nbsp;<code>queries</code>&nbsp;,包含一系列查询:</p>\n\n<ul>\n\t<li><code>queries[i] = [x, y]</code>&nbsp;:在平面上坐标&nbsp;<code>(x, y)</code>&nbsp;处建一个障碍物,数据保证之前的查询 <strong>不会</strong> 在这个坐标处建立任何障碍物。</li>\n</ul>\n\n<p>每次查询后,你需要找到离原点第 <code>k</code>&nbsp;<strong>近</strong>&nbsp;障碍物到原点的 <strong>距离</strong>&nbsp;。</p>\n\n<p>请你返回一个整数数组&nbsp;<code>results</code>&nbsp;,其中&nbsp;<code>results[i]</code>&nbsp;表示建立第 <code>i</code>&nbsp;个障碍物以后,离原地第 <code>k</code>&nbsp;近障碍物距离原点的距离。如果少于 <code>k</code>&nbsp;个障碍物,<code>results[i] == -1</code>&nbsp;。</p>\n\n<p><strong>注意</strong>,一开始&nbsp;<strong>没有</strong>&nbsp;任何障碍物。</p>\n\n<p>坐标在&nbsp;<code>(x, y)</code>&nbsp;处的点距离原点的距离定义为&nbsp;<code>|x| + |y|</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入:</b>queries = [[1,2],[3,4],[2,3],[-3,0]], k = 2</span></p>\n\n<p><span class=\"example-io\"><b>输出:</b>[-1,7,5,3]</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p>最初,不存在障碍物。</p>\n\n<ul>\n\t<li><code>queries[0]</code>&nbsp;之后,少于 2 个障碍物。</li>\n\t<li><code>queries[1]</code>&nbsp;之后,&nbsp;两个障碍物距离原点的距离分别为 3 和 7 。</li>\n\t<li><code>queries[2]</code>&nbsp;之后,障碍物距离原点的距离分别为 3 5 和 7 。</li>\n\t<li><code>queries[3]</code>&nbsp;之后,障碍物距离原点的距离分别为 335 和 7 。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入:</b>queries = [[5,5],[4,4],[3,3]], k = 1</span></p>\n\n<p><span class=\"example-io\"><b>输出:</b>[10,8,6]</span></p>\n\n<p><b>解释:</b></p>\n\n<ul>\n\t<li><code>queries[0]</code>&nbsp;之后,只有一个障碍物,距离原点距离为 10 。</li>\n\t<li><code>queries[1]</code>&nbsp;之后,障碍物距离原点距离分别为 8 和 10 。</li>\n\t<li><code>queries[2]</code>&nbsp;之后,障碍物距离原点的距离分别为 6 8 和10 。</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= queries.length &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li>所有&nbsp;<code>queries[i]</code>&nbsp;互不相同。</li>\n\t<li><code>-10<sup>9</sup> &lt;= queries[i][0], queries[i][1] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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