leetcode-problemset/leetcode-cn/originData/jump-game-vii.json

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        "question": {
            "questionId": "2001",
            "questionFrontendId": "1871",
            "categoryTitle": "Algorithms",
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            "title": "Jump Game VII",
            "titleSlug": "jump-game-vii",
            "content": "<p>You are given a <strong>0-indexed</strong> binary string <code>s</code> and two integers <code>minJump</code> and <code>maxJump</code>. In the beginning, you are standing at index <code>0</code>, which is equal to <code>&#39;0&#39;</code>. You can move from index <code>i</code> to index <code>j</code> if the following conditions are fulfilled:</p>\n\n<ul>\n\t<li><code>i + minJump &lt;= j &lt;= min(i + maxJump, s.length - 1)</code>, and</li>\n\t<li><code>s[j] == &#39;0&#39;</code>.</li>\n</ul>\n\n<p>Return <code>true</code><i> if you can reach index </i><code>s.length - 1</code><i> in </i><code>s</code><em>, or </em><code>false</code><em> otherwise.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;<u>0</u>11<u>0</u>1<u>0</u>&quot;, minJump = 2, maxJump = 3\n<strong>Output:</strong> true\n<strong>Explanation:</strong>\nIn the first step, move from index 0 to index 3. \nIn the second step, move from index 3 to index 5.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;01101110&quot;, minJump = 2, maxJump = 3\n<strong>Output:</strong> false\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> is either <code>&#39;0&#39;</code> or <code>&#39;1&#39;</code>.</li>\n\t<li><code>s[0] == &#39;0&#39;</code></li>\n\t<li><code>1 &lt;= minJump &lt;= maxJump &lt; s.length</code></li>\n</ul>\n",
            "translatedTitle": "跳跃游戏 VII",
            "translatedContent": "<p>给你一个下标从 <strong>0 </strong>开始的二进制字符串 <code>s</code> 和两个整数 <code>minJump</code> 和 <code>maxJump</code> 。一开始，你在下标 <code>0</code> 处，且该位置的值一定为 <code>'0'</code> 。当同时满足如下条件时，你可以从下标 <code>i</code> 移动到下标 <code>j</code> 处：</p>\n\n<ul>\n\t<li><code>i + minJump <= j <= min(i + maxJump, s.length - 1)</code> 且</li>\n\t<li><code>s[j] == '0'</code>.</li>\n</ul>\n\n<p>如果你可以到达 <code>s</code> 的下标<i> </i><code>s.length - 1</code> 处，请你返回 <code>true</code> ，否则返回 <code>false</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>s = \"<strong>0</strong>11<strong>0</strong>1<strong>0</strong>\", minJump = 2, maxJump = 3\n<b>输出：</b>true\n<strong>解释：</strong>\n第一步，从下标 0 移动到下标 3 。\n第二步，从下标 3 移动到下标 5 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>s = \"01101110\", minJump = 2, maxJump = 3\n<b>输出：</b>false\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> 要么是 <code>'0'</code> ，要么是 <code>'1'</code></li>\n\t<li><code>s[0] == '0'</code></li>\n\t<li><code>1 <= minJump <= maxJump < s.length</code></li>\n</ul>\n",
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