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"question": {
"questionId": "1472",
"questionFrontendId": "1370",
"categoryTitle": "Algorithms",
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"title": "Increasing Decreasing String",
"titleSlug": "increasing-decreasing-string",
"content": "<p>You are given a string <code>s</code>. Reorder the string using the following algorithm:</p>\n\n<ol>\n\t<li>Remove the <strong>smallest</strong> character from <code>s</code> and <strong>append</strong> it to the result.</li>\n\t<li>Remove the <strong>smallest</strong> character from <code>s</code> that is greater than the last appended character, and <strong>append</strong> it to the result.</li>\n\t<li>Repeat step 2 until no more characters can be removed.</li>\n\t<li>Remove the <strong>largest</strong> character from <code>s</code> and <strong>append</strong> it to the result.</li>\n\t<li>Remove the <strong>largest</strong> character from <code>s</code> that is smaller than the last appended character, and <strong>append</strong> it to the result.</li>\n\t<li>Repeat step 5 until no more characters can be removed.</li>\n\t<li>Repeat steps 1 through 6 until all characters from <code>s</code> have been removed.</li>\n</ol>\n\n<p>If the smallest or largest character appears more than once, you may choose any occurrence to append to the result.</p>\n\n<p>Return the resulting string after reordering <code>s</code> using this algorithm.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aaaabbbbcccc&quot;\n<strong>Output:</strong> &quot;abccbaabccba&quot;\n<strong>Explanation:</strong> After steps 1, 2 and 3 of the first iteration, result = &quot;abc&quot;\nAfter steps 4, 5 and 6 of the first iteration, result = &quot;abccba&quot;\nFirst iteration is done. Now s = &quot;aabbcc&quot; and we go back to step 1\nAfter steps 1, 2 and 3 of the second iteration, result = &quot;abccbaabc&quot;\nAfter steps 4, 5 and 6 of the second iteration, result = &quot;abccbaabccba&quot;\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;rat&quot;\n<strong>Output:</strong> &quot;art&quot;\n<strong>Explanation:</strong> The word &quot;rat&quot; becomes &quot;art&quot; after re-ordering it with the mentioned algorithm.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 500</code></li>\n\t<li><code>s</code> consists of only lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "上升下降字符串",
"translatedContent": "<p>给你一个字符串&nbsp;<code>s</code>&nbsp;,请你根据下面的算法重新构造字符串:</p>\n\n<ol>\n\t<li>从 <code>s</code>&nbsp;中选出 <strong>最小</strong>&nbsp;的字符,将它 <strong>接在</strong>&nbsp;结果字符串的后面。</li>\n\t<li>从 <code>s</code> 剩余字符中选出比上一个添加字符更大的 <strong>最小</strong> 字符,将它 <strong>接在</strong>&nbsp;结果字符串后面。</li>\n\t<li>重复步骤 2 ,直到你没法从 <code>s</code>&nbsp;中选择字符。</li>\n\t<li>从 <code>s</code>&nbsp;中选出 <strong>最大</strong>&nbsp;的字符,将它 <strong>接在</strong>&nbsp;结果字符串的后面。</li>\n\t<li>从 <code>s</code> 剩余字符中选出比上一个添加字符更小的 <strong>最大</strong>&nbsp;字符,将它 <strong>接在</strong>&nbsp;结果字符串后面。</li>\n\t<li>重复步骤 5&nbsp;,直到你没法从 <code>s</code>&nbsp;中选择字符。</li>\n\t<li>重复步骤 1 到 6 ,直到 <code>s</code>&nbsp;中所有字符都已经被选过。</li>\n</ol>\n\n<p>在任何一步中,如果最小或者最大字符不止一个&nbsp;,你可以选择其中任意一个,并将其添加到结果字符串。</p>\n\n<p>请你返回将&nbsp;<code>s</code>&nbsp;中字符重新排序后的 <strong>结果字符串</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"aaaabbbbcccc\"\n<strong>输出:</strong>\"abccbaabccba\"\n<strong>解释:</strong>第一轮的步骤 123 后,结果字符串为 result = \"abc\"\n第一轮的步骤 456 后,结果字符串为 result = \"abccba\"\n第一轮结束现在 s = \"aabbcc\" ,我们再次回到步骤 1\n第二轮的步骤 123 后,结果字符串为 result = \"abccbaabc\"\n第二轮的步骤 456 后,结果字符串为 result = \"abccbaabccba\"\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"rat\"\n<strong>输出:</strong>\"art\"\n<strong>解释:</strong>单词 \"rat\" 在上述算法重排序以后变成 \"art\"\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 500</code></li>\n\t<li><code>s</code>&nbsp;只包含小写英文字母。</li>\n</ul>\n",
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"Loop over all character from 'a' to 'z' and append the character if it exists and decrease frequency by 1. Do the same from 'z' to 'a'.",
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