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leetcode-problemset/leetcode-cn/originData/find-winner-on-a-tic-tac-toe-game.json
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"title": "Find Winner on a Tic Tac Toe Game",
"titleSlug": "find-winner-on-a-tic-tac-toe-game",
"content": "<p><strong>Tic-tac-toe</strong> is played by two players <code>A</code> and <code>B</code> on a <code>3 x 3</code> grid. The rules of Tic-Tac-Toe are:</p>\n\n<ul>\n\t<li>Players take turns placing characters into empty squares <code>&#39; &#39;</code>.</li>\n\t<li>The first player <code>A</code> always places <code>&#39;X&#39;</code> characters, while the second player <code>B</code> always places <code>&#39;O&#39;</code> characters.</li>\n\t<li><code>&#39;X&#39;</code> and <code>&#39;O&#39;</code> characters are always placed into empty squares, never on filled ones.</li>\n\t<li>The game ends when there are <strong>three</strong> of the same (non-empty) character filling any row, column, or diagonal.</li>\n\t<li>The game also ends if all squares are non-empty.</li>\n\t<li>No more moves can be played if the game is over.</li>\n</ul>\n\n<p>Given a 2D integer array <code>moves</code> where <code>moves[i] = [row<sub>i</sub>, col<sub>i</sub>]</code> indicates that the <code>i<sup>th</sup></code> move will be played on <code>grid[row<sub>i</sub>][col<sub>i</sub>]</code>. return <em>the winner of the game if it exists</em> (<code>A</code> or <code>B</code>). In case the game ends in a draw return <code>&quot;Draw&quot;</code>. If there are still movements to play return <code>&quot;Pending&quot;</code>.</p>\n\n<p>You can assume that <code>moves</code> is valid (i.e., it follows the rules of <strong>Tic-Tac-Toe</strong>), the grid is initially empty, and <code>A</code> will play first.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/22/xo1-grid.jpg\" style=\"width: 244px; height: 245px;\" />\n<pre>\n<strong>Input:</strong> moves = [[0,0],[2,0],[1,1],[2,1],[2,2]]\n<strong>Output:</strong> &quot;A&quot;\n<strong>Explanation:</strong> A wins, they always play first.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/22/xo2-grid.jpg\" style=\"width: 244px; height: 245px;\" />\n<pre>\n<strong>Input:</strong> moves = [[0,0],[1,1],[0,1],[0,2],[1,0],[2,0]]\n<strong>Output:</strong> &quot;B&quot;\n<strong>Explanation:</strong> B wins.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/22/xo3-grid.jpg\" style=\"width: 244px; height: 245px;\" />\n<pre>\n<strong>Input:</strong> moves = [[0,0],[1,1],[2,0],[1,0],[1,2],[2,1],[0,1],[0,2],[2,2]]\n<strong>Output:</strong> &quot;Draw&quot;\n<strong>Explanation:</strong> The game ends in a draw since there are no moves to make.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= moves.length &lt;= 9</code></li>\n\t<li><code>moves[i].length == 2</code></li>\n\t<li><code>0 &lt;= row<sub>i</sub>, col<sub>i</sub> &lt;= 2</code></li>\n\t<li>There are no repeated elements on <code>moves</code>.</li>\n\t<li><code>moves</code> follow the rules of tic tac toe.</li>\n</ul>\n",
"translatedTitle": "找出井字棋的获胜者",
"translatedContent": "<p><strong>井字棋&nbsp;</strong>是由两个玩家<i>&nbsp;</i><code>A</code>&nbsp;和&nbsp;<code>B</code>&nbsp;在&nbsp;<code>3 x 3</code>&nbsp;的棋盘上进行的游戏。井字棋游戏的规则如下:</p>\n\n<ul>\n\t<li>玩家轮流将棋子放在空方格 (<code>' '</code>) 上。</li>\n\t<li>第一个玩家 <code>A</code> 总是用&nbsp;<code>'X'</code> 作为棋子,而第二个玩家 <code>B</code> 总是用 <code>'O'</code> 作为棋子。</li>\n\t<li><code>'X'</code> 和 <code>'O'</code> 只能放在空方格中,而不能放在已经被占用的方格上。</li>\n\t<li>只要有 <strong>3</strong> 个相同的(非空)棋子排成一条直线(行、列、对角线)时,游戏结束。</li>\n\t<li>如果所有方块都放满棋子(不为空),游戏也会结束。</li>\n\t<li>游戏结束后,棋子无法再进行任何移动。</li>\n</ul>\n\n<p>给你一个数组 <code>moves</code>,其中 <code>moves[i] = [row<sub>i</sub>, col<sub>i</sub>]</code>&nbsp;表示第&nbsp;<code>i</code>&nbsp;次移动在&nbsp;<code>grid[row<sub>i</sub>][col<sub>i</sub>]</code>。如果游戏存在获胜者(<code>A</code> 或 <code>B</code>),就返回该游戏的获胜者;如果游戏以平局结束,则返回 <code>\"Draw\"</code>;如果仍会有行动(游戏未结束),则返回 <code>\"Pending\"</code>。</p>\n\n<p>你可以假设&nbsp;<code>moves</code>&nbsp;都 <strong>有效</strong>(遵循 <strong>井字棋</strong> 规则),网格最初是空的,<code>A</code> 将先行动。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/22/xo1-grid.jpg\" style=\"width: 244px; height: 245px;\" />\n<pre>\n<strong>输入:</strong>moves = [[0,0],[2,0],[1,1],[2,1],[2,2]]\n<strong>输出:</strong>\"A\"\n<strong>解释:</strong>\"A\" 获胜,他总是先走。\n</pre>\n\n<p><strong>示例 2</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/22/xo2-grid.jpg\" style=\"width: 244px; height: 245px;\" />\n<pre>\n<strong>输入:</strong>moves = [[0,0],[1,1],[0,1],[0,2],[1,0],[2,0]]\n<strong>输出:</strong>\"B\"\n<strong>解释:</strong>\"B\" 获胜。\n</pre>\n\n<p><strong>示例 3</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/22/xo3-grid.jpg\" style=\"width: 244px; height: 245px;\" />\n<pre>\n<strong>输入:</strong>moves = [[0,0],[1,1],[2,0],[1,0],[1,2],[2,1],[0,1],[0,2],[2,2]]\n<strong>输出:</strong>\"Draw\"\n<strong>解释:</strong>由于没有办法再行动,游戏以平局结束。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= moves.length &lt;= 9</code></li>\n\t<li><code>moves[i].length == 2</code></li>\n\t<li><code>0 &lt;= moves[i][j] &lt;= 2</code></li>\n\t<li><code>moves</code>&nbsp;里没有重复的元素。</li>\n\t<li><code>moves</code> 遵循井字棋的规则。</li>\n</ul>\n",
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