leetcode-problemset/leetcode-cn/originData/find-the-maximum-divisibility-score.json

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        "question": {
            "questionId": "2694",
            "questionFrontendId": "2644",
            "categoryTitle": "Algorithms",
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            "title": "Find the Maximum Divisibility Score",
            "titleSlug": "find-the-maximum-divisibility-score",
            "content": "<p>You are given two integer arrays <code>nums</code> and <code>divisors</code>.</p>\n\n<p>The <strong>divisibility score</strong> of <code>divisors[i]</code> is the number of indices <code>j</code> such that <code>nums[j]</code> is divisible by <code>divisors[i]</code>.</p>\n\n<p>Return the integer <code>divisors[i]</code> with the <strong>maximum</strong> divisibility score. If multiple integers have the maximum score, return the smallest one.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,9,15,50], divisors = [5,3,7,2]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The divisibility score of <code>divisors[0]</code> is 2 since <code>nums[2]</code> and <code>nums[3]</code> are divisible by 5.</p>\n\n<p>The divisibility score of <code>divisors[1]</code> is 2 since <code>nums[1]</code> and <code>nums[2]</code> are divisible by 3.</p>\n\n<p>The divisibility score of <code>divisors[2]</code> is 0 since none of the numbers in <code>nums</code> is divisible by 7.</p>\n\n<p>The divisibility score of <code>divisors[3]</code> is 2 since <code>nums[0]</code> and <code>nums[3]</code> are divisible by 2.</p>\n\n<p>As <code>divisors[0]</code>,&nbsp;<code>divisors[1]</code>, and <code>divisors[3]</code> have the same divisibility score, we return the smaller one which is <code>divisors[3]</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [4,7,9,3,9], divisors = [5,2,3]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The divisibility score of <code>divisors[0]</code> is 0 since none of numbers in <code>nums</code> is divisible by 5.</p>\n\n<p>The divisibility score of <code>divisors[1]</code> is 1 since only <code>nums[0]</code> is divisible by 2.</p>\n\n<p>The divisibility score of <code>divisors[2]</code> is 3 since <code>nums[2]</code>, <code>nums[3]</code> and <code>nums[4]</code> are divisible by 3.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [20,14,21,10], divisors = [10,16,20]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">10</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The divisibility score of <code>divisors[0]</code> is 2 since <code>nums[0]</code> and <code>nums[3]</code> are divisible by 10.</p>\n\n<p>The divisibility score of <code>divisors[1]</code> is 0 since none of the numbers in <code>nums</code> is divisible by 16.</p>\n\n<p>The divisibility score of <code>divisors[2]</code> is 1 since <code>nums[0]</code> is divisible by 20.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length, divisors.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i], divisors[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "找出可整除性得分最大的整数",
            "translatedContent": "<p>给你两个整数数组 <code>nums</code> 和 <code>divisors</code> 。</p>\n\n<p><code>divisors[i]</code> 的 <strong>可整除性得分</strong> 等于满足 <code>nums[j]</code> 能被 <code>divisors[i]</code> 整除的下标 <code>j</code> 的数量。</p>\n\n<p>返回 <strong>可整除性得分</strong> 最大的整数 <code>divisors[i]</code> 。如果有多个整数具有最大得分，则返回数值最小的一个。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">nums = [2,9,15,50], divisors = [5,3,7,2]</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">2</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p><code>divisors[0]</code>&nbsp;的可整除性分数为 2 因为&nbsp;<code>nums[2]</code> 和&nbsp;<code>nums[3]</code>&nbsp;能被 5 整除。</p>\n\n<p><code>divisors[1]</code> 的可整除性分数为 2 因为&nbsp;<code>nums[1]</code>&nbsp;和&nbsp;<code>nums[2]</code>&nbsp;能被 3 整除。</p>\n\n<p><code>divisors[2]</code> 的可整除性分数为 0 因为&nbsp;<code>nums</code>&nbsp;中没有数字能被 7 整除。</p>\n\n<p><code>divisors[3]</code> 的可整除性分数为 2 因为 <code>nums[0]</code> 和&nbsp;<code>nums[3]</code>&nbsp;能够被 2 整除。</p>\n\n<p>因为&nbsp;<code>divisors[0]</code>&nbsp;、<code>divisor[1]</code> 和&nbsp;<code>divisors[3]</code>&nbsp;有相同的可整除性分数，我们返回更小的那个&nbsp;<code>divisors[3]</code>。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">nums = [4,7,9,3,9], divisors = [5,2,3]</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">3</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p><code>divisors[0]</code> 的可整除性分数为 0&nbsp;因为&nbsp;<code>nums</code>&nbsp;中没有数字能被 5 整除。</p>\n\n<p><code>divisors[1]</code> 的可整除性分数为 1 因为只有 <code>nums[0]</code>&nbsp;能被 2 整除。</p>\n\n<p><code>divisors[2]</code> 的可整除性分数为 3 因为&nbsp;<code>nums[2]</code>&nbsp;，<code>nums[3]</code>&nbsp;和&nbsp;<code>nums[4]</code>&nbsp;能被 3 整除。</p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">nums = [20,14,21,10], divisors = [10,16,20]</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">10</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p><code>divisors[0]</code> 的可整除性分数为 2 因为&nbsp;<code>nums[0]</code>&nbsp;和&nbsp;<code>nums[3]</code> 能被 10 整除。</p>\n\n<p><code>divisors[1]</code> 的可整除性分数为 0 因为&nbsp;<code>nums</code>&nbsp;中没有数字能被 16&nbsp;整除。</p>\n\n<p><code>divisors[2]</code> 的可整除性分数为 1 因为&nbsp;<code>nums[0]</code>&nbsp;能被 20&nbsp;整除。</p>\n\n<p>因为&nbsp;<code>divisors[0]</code>&nbsp;的可整除性分数最大，我们返回&nbsp;<code>divisors[0]</code>。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length, divisors.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i], divisors[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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\\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.11<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u4f7f\\u7528\\u7684\\u662f JetBrains \\u63d0\\u4f9b\\u7684 experimental compiler\\u3002\\u5982\\u679c\\u60a8\\u8ba4\\u4e3a\\u60a8\\u9047\\u5230\\u4e86\\u7f16\\u8bd1\\u5668\\u76f8\\u5173\\u7684\\u95ee\\u9898\\uff0c\\u8bf7\\u5411\\u6211\\u4eec\\u53cd\\u9988<\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.79.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a> \\u548c <a href=\\\"https:\\/\\/crates.io\\/crates\\/regex\\\" target=\\\"_blank\\\">regex<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.1.6<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2022<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/priority-queue\\/blob\\/v5\\/README.md\\\" target=\\\"_blank\\\"> datastructures-js\\/priority-queue@5.4.0<\\/a>\\uff0c<a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\/tree\\/v4.2.3\\\" target=\\\"_blank\\\"> datastructures-js\\/queue@4.2.3<\\/a> \\u4ee5\\u53ca <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/deque\\/tree\\/v1.0.4\\\" target=\\\"_blank\\\"> datastructures-js\\/deque@1.0.4<\\/a>\\u3002<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.15<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 26\"],\"elixir\":[\"Elixir\",\"Elixir 1.17 with Erlang\\/OTP 26\"],\"dart\":[\"Dart\",\"<p>Dart 3.2\\u3002\\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/pub.dev\\/packages\\/collection\\/versions\\/1.18.0\\\" target=\\\"_blank\\\">collection<\\/a> \\u5305<\\/p>\\r\\n\\r\\n<p>\\u60a8\\u7684\\u4ee3\\u7801\\u5c06\\u4f1a\\u88ab\\u4e0d\\u7f16\\u8bd1\\u76f4\\u63a5\\u8fd0\\u884c<\\/p>\"],\"cangjie\":[\"Cangjie\",\"<p>\\u7248\\u672c\\uff1a0.53.11 (cjnative)<\\/p>\\r\\n\\r\\n<p>\\u7f16\\u8bd1\\u53c2\\u6570\\uff1a<code>-O2 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