leetcode-problemset/leetcode-cn/originData/find-the-maximum-achievable-number.json

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            "questionId": "2812",
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            "title": "Find the Maximum Achievable Number",
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            "content": "<p>Given two integers, <code>num</code> and <code>t</code>. A <strong>number </strong><code>x</code><strong> </strong>is<strong> achievable</strong> if it can become equal to <code>num</code> after applying the following operation <strong>at most</strong> <code>t</code> times:</p>\n\n<ul>\n\t<li>Increase or decrease <code>x</code> by <code>1</code>, and <em>simultaneously</em> increase or decrease <code>num</code> by <code>1</code>.</li>\n</ul>\n\n<p>Return the <strong>maximum </strong>possible value of <code>x</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">num = 4, t = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">6</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Apply the following operation once to make the maximum achievable number equal to <code>num</code>:</p>\n\n<ul>\n\t<li>Decrease the maximum achievable number by 1, and increase <code>num</code> by 1.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">num = 3, t = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">7</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Apply the following operation twice to make the maximum achievable number equal to <code>num</code>:</p>\n\n<ul>\n\t<li>Decrease the maximum achievable number by 1, and increase <code>num</code> by 1.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= num, t&nbsp;&lt;= 50</code></li>\n</ul>\n",
            "translatedTitle": "找出最大的可达成数字",
            "translatedContent": "<p>给你两个整数 <code>num</code> 和 <code>t</code> 。如果整数 <code>x</code> 可以在执行下述操作 <strong>不超过</strong> <code>t</code> 次的情况下变为与 <code>num</code> 相等，则称其为 <strong>可达成数字</strong> ：</p>\n\n<ul>\n\t<li>每次操作将 <code>x</code> 的值增加或减少 <code>1</code> ，同时可以选择将 <code>num</code> 的值增加或减少 <code>1</code> 。</li>\n</ul>\n\n<p>返回所有可达成数字中的 <strong>最大</strong> 值 <code>x</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong>num = 4, t = 1</p>\n\n<p><strong>输出：</strong>6</p>\n\n<p><strong>解释：</strong></p>\n\n<p>执行下述操作可以使最大可达成数字等于 <code>num</code> ：</p>\n\n<ul>\n\t<li>最大可达成数字减少 1 ，同时 <code>num</code> 增加 1 。</li>\n</ul>\n</div>\n\n<p><strong>示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong>num = 3, t = 2</p>\n\n<p><strong>输出：</strong>7</p>\n\n<p><strong>解释：</strong></p>\n\n<p>执行两次下述操作可以使最大可达成数字等于 num ：</p>\n\n<ul>\n\t<li>最大可达成数字减少 1 ，同时 <code>num</code> 增加 1。</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= num, t&nbsp;&lt;= 50</code></li>\n</ul>\n",
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