leetcode-problemset/leetcode-cn/originData/er-cha-shu-de-jing-xiang-lcof.json

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    "data": {
        "question": {
            "questionId": "100288",
            "questionFrontendId": "LCR 144",
            "categoryTitle": "Algorithms",
            "boundTopicId": 86201,
            "title": "翻转二叉树",
            "titleSlug": "er-cha-shu-de-jing-xiang-lcof",
            "content": "English description is not available for the problem. Please switch to Chinese.",
            "translatedTitle": "翻转二叉树",
            "translatedContent": "<p>给定一棵二叉树的根节点 <code>root</code>，请左右翻转这棵二叉树，并返回其根节点。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://pic.leetcode.cn/1694686821-qlvjod-%E7%BF%BB%E8%BD%AC%E4%BA%8C%E5%8F%89%E6%A0%91.png\" /></p>\n\n<pre>\n<strong>输入：</strong>root = [5,7,9,8,3,2,4]\n<strong>输出：</strong>[5,9,7,4,2,3,8]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点数目范围在 <code>[0, 100]</code> 内</li>\n\t<li><code>-100 &lt;= Node.val &lt;= 100</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p>注意：本题与主站 226 题相同：<a href=\"https://leetcode-cn.com/problems/invert-binary-tree/\">https://leetcode-cn.com/problems/invert-binary-tree/</a></p>\n\n<p>&nbsp;</p>\n",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     TreeNode *left;\n *     TreeNode *right;\n *     TreeNode() : val(0), left(nullptr), right(nullptr) {}\n *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n    TreeNode* flipTree(TreeNode* root) {\n        \n    }\n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.left = (left===undefined ? null : left)\n *     this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {TreeNode}\n */\nvar flipTree = function(root) {\n    \n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *     val: number\n *     left: TreeNode | null\n *     right: TreeNode | null\n *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.left = (left===undefined ? null : left)\n *         this.right = (right===undefined ? null : right)\n *     }\n * }\n */\n\nfunction flipTree(root: TreeNode | null): TreeNode | null {\n    \n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     public var val: Int\n *     public var left: TreeNode?\n *     public var right: TreeNode?\n *     public init() { self.val = 0; self.left = nil; self.right = nil; }\n *     public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n *     public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n *         self.val = val\n *         self.left = left\n *         self.right = right\n *     }\n * }\n */\nclass Solution {\n    func flipTree(_ root: TreeNode?) -> TreeNode? {\n        \n    }\n}",
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                    "code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n *     var left: TreeNode? = null\n *     var right: TreeNode? = null\n * }\n */\nclass Solution {\n    fun flipTree(root: TreeNode?): TreeNode? {\n        \n    }\n}",
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                    "code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%%                     left = null  :: 'null' | #tree_node{},\n%%                     right = null :: 'null' | #tree_node{}}).\n\n-spec flip_tree(Root :: #tree_node{} | null) -> #tree_node{} | null.\nflip_tree(Root) ->\n  .",
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