leetcode-problemset/leetcode-cn/originData/divide-array-into-arrays-with-max-difference.json

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            "questionId": "3241",
            "questionFrontendId": "2966",
            "categoryTitle": "Algorithms",
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            "title": "Divide Array Into Arrays With Max Difference",
            "titleSlug": "divide-array-into-arrays-with-max-difference",
            "content": "<p>You are given an integer array <code>nums</code> of size <code>n</code> where <code>n</code> is a multiple of 3 and a positive integer <code>k</code>.</p>\n\n<p>Divide the array <code>nums</code> into <code>n / 3</code> arrays of size <strong>3</strong> satisfying the following condition:</p>\n\n<ul>\n\t<li>The difference between <strong>any</strong> two elements in one array is <strong>less than or equal</strong> to <code>k</code>.</li>\n</ul>\n\n<p>Return a <strong>2D</strong> array containing the arrays. If it is impossible to satisfy the conditions, return an empty array. And if there are multiple answers, return <strong>any</strong> of them.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,3,4,8,7,9,3,5,1], k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[[1,1,3],[3,4,5],[7,8,9]]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The difference between any two elements in each array is less than or equal to 2.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,4,2,2,5,2], k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Different ways to divide <code>nums</code> into 2 arrays of size 3 are:</p>\n\n<ul>\n\t<li>[[2,2,2],[2,4,5]] (and its permutations)</li>\n\t<li>[[2,2,4],[2,2,5]] (and its permutations)</li>\n</ul>\n\n<p>Because there are four 2s there will be an array with the elements 2 and 5 no matter how we divide it. since <code>5 - 2 = 3 &gt; k</code>, the condition is not satisfied and so there is no valid division.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [4,2,9,8,2,12,7,12,10,5,8,5,5,7,9,2,5,11], k = 14</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[[2,2,12],[4,8,5],[5,9,7],[7,8,5],[5,9,10],[11,12,2]]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The difference between any two elements in each array is less than or equal to 14.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>n </code>is a multiple of 3</li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "划分数组并满足最大差限制",
            "translatedContent": "<p>给你一个长度为 <code>n</code> 的整数数组 <code>nums</code>，以及一个正整数 <code>k</code> 。</p>\n\n<p>将这个数组划分为&nbsp;<code>n / 3</code>&nbsp;个长度为 <code>3</code> 的子数组，并满足以下条件：</p>\n\n<ul>\n\t<li>子数组中<strong> 任意 </strong>两个元素的差必须 <strong>小于或等于</strong> <code>k</code> 。</li>\n</ul>\n\n<p>返回一个<em> </em><strong>二维数组 </strong>，包含所有的子数组。如果不可能满足条件，就返回一个空数组。如果有多个答案，返回 <strong>任意一个</strong> 即可。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [1,3,4,8,7,9,3,5,1], k = 2</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[[1,1,3],[3,4,5],[7,8,9]]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>每个数组中任何两个元素之间的差小于或等于 2。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b></span><span class=\"example-io\">nums = [2,4,2,2,5,2], k = 2</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b></span><span class=\"example-io\">[]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>将&nbsp;<code>nums</code>&nbsp;划分为 2 个长度为 3 的数组的不同方式有：</p>\n\n<ul>\n\t<li>[[2,2,2],[2,4,5]] （及其排列）</li>\n\t<li>[[2,2,4],[2,2,5]] （及其排列）</li>\n</ul>\n\n<p>因为有四个 2，所以无论我们如何划分，都会有一个包含元素 2 和 5 的数组。因为&nbsp;<code>5 - 2 = 3 &gt; k</code>，条件无法被满足，所以没有合法的划分。</p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b></span><span class=\"example-io\">nums = [4,2,9,8,2,12,7,12,10,5,8,5,5,7,9,2,5,11], k = 14</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b></span><span class=\"example-io\">[[2,2,12],[4,8,5],[5,9,7],[7,8,5],[5,9,10],[11,12,2]]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>每个数组中任何两个元素之间的差小于或等于 14。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>n</code> 是 <code>3</code> 的倍数</li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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\\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.11<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u4f7f\\u7528\\u7684\\u662f JetBrains \\u63d0\\u4f9b\\u7684 experimental compiler\\u3002\\u5982\\u679c\\u60a8\\u8ba4\\u4e3a\\u60a8\\u9047\\u5230\\u4e86\\u7f16\\u8bd1\\u5668\\u76f8\\u5173\\u7684\\u95ee\\u9898\\uff0c\\u8bf7\\u5411\\u6211\\u4eec\\u53cd\\u9988<\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.79.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a> \\u548c <a href=\\\"https:\\/\\/crates.io\\/crates\\/regex\\\" target=\\\"_blank\\\">regex<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.1.6<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2022<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/priority-queue\\/blob\\/v5\\/README.md\\\" target=\\\"_blank\\\"> datastructures-js\\/priority-queue@5.4.0<\\/a>\\uff0c<a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\/tree\\/v4.2.3\\\" target=\\\"_blank\\\"> datastructures-js\\/queue@4.2.3<\\/a> \\u4ee5\\u53ca <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/deque\\/tree\\/v1.0.4\\\" target=\\\"_blank\\\"> datastructures-js\\/deque@1.0.4<\\/a>\\u3002<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.15<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 26\"],\"elixir\":[\"Elixir\",\"Elixir 1.17 with Erlang\\/OTP 26\"],\"dart\":[\"Dart\",\"<p>Dart 3.2\\u3002\\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/pub.dev\\/packages\\/collection\\/versions\\/1.18.0\\\" target=\\\"_blank\\\">collection<\\/a> \\u5305<\\/p>\\r\\n\\r\\n<p>\\u60a8\\u7684\\u4ee3\\u7801\\u5c06\\u4f1a\\u88ab\\u4e0d\\u7f16\\u8bd1\\u76f4\\u63a5\\u8fd0\\u884c<\\/p>\"],\"cangjie\":[\"Cangjie\",\"<p>\\u7248\\u672c\\uff1a0.53.11 (cjnative)<\\/p>\\r\\n\\r\\n<p>\\u7f16\\u8bd1\\u53c2\\u6570\\uff1a<code>-O2 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