leetcode-problemset/leetcode-cn/originData/compare-version-numbers.json

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        "question": {
            "questionId": "165",
            "questionFrontendId": "165",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1849,
            "title": "Compare Version Numbers",
            "titleSlug": "compare-version-numbers",
            "content": "<p>Given two <strong>version strings</strong>, <code>version1</code> and <code>version2</code>, compare them. A version string consists of <strong>revisions</strong> separated by dots <code>&#39;.&#39;</code>. The <strong>value of the revision</strong> is its <strong>integer conversion</strong> ignoring leading zeros.</p>\n\n<p>To compare version strings, compare their revision values in <strong>left-to-right order</strong>. If one of the version strings has fewer revisions, treat the missing revision values as <code>0</code>.</p>\n\n<p>Return the following:</p>\n\n<ul>\n\t<li>If <code>version1 &lt; version2</code>, return -1.</li>\n\t<li>If <code>version1 &gt; version2</code>, return 1.</li>\n\t<li>Otherwise, return 0.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">version1 = &quot;1.2&quot;, version2 = &quot;1.10&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">-1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>version1&#39;s second revision is &quot;2&quot; and version2&#39;s second revision is &quot;10&quot;: 2 &lt; 10, so version1 &lt; version2.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">version1 = &quot;1.01&quot;, version2 = &quot;1.001&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Ignoring leading zeroes, both &quot;01&quot; and &quot;001&quot; represent the same integer &quot;1&quot;.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">version1 = &quot;1.0&quot;, version2 = &quot;1.0.0.0&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>version1 has less revisions, which means every missing revision are treated as &quot;0&quot;.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= version1.length, version2.length &lt;= 500</code></li>\n\t<li><code>version1</code> and <code>version2</code>&nbsp;only contain digits and <code>&#39;.&#39;</code>.</li>\n\t<li><code>version1</code> and <code>version2</code>&nbsp;<strong>are valid version numbers</strong>.</li>\n\t<li>All the given revisions in&nbsp;<code>version1</code> and <code>version2</code>&nbsp;can be stored in&nbsp;a&nbsp;<strong>32-bit integer</strong>.</li>\n</ul>\n",
            "translatedTitle": "比较版本号",
            "translatedContent": "<p>给你两个 <strong>版本号字符串</strong>&nbsp;<code>version1</code> 和 <code>version2</code> ，请你比较它们。版本号由被点&nbsp;<code>'.'</code> 分开的修订号组成。<strong>修订号的值</strong> 是它 <strong>转换为整数</strong> 并忽略前导零。</p>\n\n<p>比较版本号时，请按 <strong>从左到右的顺序</strong> 依次比较它们的修订号。如果其中一个版本字符串的修订号较少，则将缺失的修订号视为 <code>0</code>。</p>\n\n<p>返回规则如下：</p>\n\n<ul>\n\t<li>如果&nbsp;<code><em>version1&nbsp;</em>&lt;&nbsp;<em>version2</em></code> 返回 <code>-1</code>，</li>\n\t<li>如果&nbsp;<code><em>version1&nbsp;</em>&gt;&nbsp;<em>version2</em></code>&nbsp;返回&nbsp;<code>1</code>，</li>\n\t<li>除此之外返回 <code>0</code>。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">version1 = \"1.2\", version2 = \"1.10\"</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">-1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>version1 的第二个修订号为&nbsp;\"2\"，version2 的第二个修订号为 \"10\"：2 &lt; 10，所以 version1 &lt; version2。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">version1 = \"1.01\", version2 = \"1.001\"</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">0</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>忽略前导零，\"01\" 和 \"001\" 都代表相同的整数 \"1\"。</p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">version1 = \"1.0\", version2 = \"1.0.0.0\"</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">0</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>version1 有更少的修订号，每个缺失的修订号按 \"0\" 处理。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= version1.length, version2.length &lt;= 500</code></li>\n\t<li><code>version1</code> 和 <code>version2</code> 仅包含数字和 <code>'.'</code></li>\n\t<li><code>version1</code> 和 <code>version2</code> 都是 <strong>有效版本号</strong></li>\n\t<li><code>version1</code> 和 <code>version2</code> 的所有修订号都可以存储在 <strong>32 位整数</strong> 中</li>\n</ul>\n",
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                "You can use two pointers for each version string to traverse them together while comparing the corresponding segments.",
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