leetcode-problemset/leetcode-cn/originData/binary-subarrays-with-sum.json

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            "title": "Binary Subarrays With Sum",
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            "content": "<p>Given a binary array <code>nums</code> and an integer <code>goal</code>, return <em>the number of non-empty <strong>subarrays</strong> with a sum</em> <code>goal</code>.</p>\n\n<p>A <strong>subarray</strong> is a contiguous part of the array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,0,1,0,1], goal = 2\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The 4 subarrays are bolded and underlined below:\n[<u><strong>1,0,1</strong></u>,0,1]\n[<u><strong>1,0,1,0</strong></u>,1]\n[1,<u><strong>0,1,0,1</strong></u>]\n[1,0,<u><strong>1,0,1</strong></u>]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,0,0,0,0], goal = 0\n<strong>Output:</strong> 15\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>nums[i]</code> is either <code>0</code> or <code>1</code>.</li>\n\t<li><code>0 &lt;= goal &lt;= nums.length</code></li>\n</ul>\n",
            "translatedTitle": "和相同的二元子数组",
            "translatedContent": "<p>给你一个二元数组 <code>nums</code> ，和一个整数 <code>goal</code> ，请你统计并返回有多少个和为 <code>goal</code> 的<strong> 非空</strong> 子数组。</p>\n\n<p><strong>子数组</strong> 是数组的一段连续部分。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,0,1,0,1], goal = 2\n<strong>输出：</strong>4\n<strong>解释：</strong>\n有 4 个满足题目要求的子数组：[1,0,1]、[1,0,1,0]、[0,1,0,1]、[1,0,1]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0,0,0,0,0], goal = 0\n<strong>输出：</strong>15\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 3 * 10<sup>4</sup></code></li>\n\t<li><code>nums[i]</code> 不是 <code>0</code> 就是 <code>1</code></li>\n\t<li><code>0 <= goal <= nums.length</code></li>\n</ul>\n",
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