leetcode-problemset/leetcode-cn/originData/bag-of-tokens.json

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        "question": {
            "questionId": "985",
            "questionFrontendId": "948",
            "categoryTitle": "Algorithms",
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            "title": "Bag of Tokens",
            "titleSlug": "bag-of-tokens",
            "content": "<p>You start with an initial <strong>power</strong> of <code>power</code>, an initial <strong>score</strong> of <code>0</code>, and a bag of tokens given as an integer array <code>tokens</code>, where each&nbsp;<code>tokens[i]</code> denotes the value of token<em><sub>i</sub></em>.</p>\n\n<p>Your goal is to <strong>maximize</strong> the total <strong>score</strong> by strategically playing these tokens. In one move, you can play an <strong>unplayed</strong> token in one of the two ways (but not both for the same token):</p>\n\n<ul>\n\t<li><strong>Face-up</strong>: If your current power is <strong>at least</strong> <code>tokens[i]</code>, you may play token<em><sub>i</sub></em>, losing <code>tokens[i]</code> power and gaining <code>1</code> score.</li>\n\t<li><strong>Face-down</strong>: If your current score is <strong>at least</strong> <code>1</code>, you may play token<em><sub>i</sub></em>, gaining <code>tokens[i]</code> power and losing <code>1</code> score.</li>\n</ul>\n\n<p>Return <em>the <strong>maximum</strong> possible score you can achieve after playing <strong>any</strong> number of tokens</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\" style=\"\n    border-color: var(--border-tertiary);\n    border-left-width: 2px;\n    color: var(--text-secondary);\n    font-size: .875rem;\n    margin-bottom: 1rem;\n    margin-top: 1rem;\n    overflow: visible;\n    padding-left: 1rem;\n\">\n<p><strong>Input:</strong> <span class=\"example-io\" style=\"\n    font-family: Menlo,sans-serif;\n    font-size: 0.85rem;\n\">tokens = [100], power = 50</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\" style=\"\n    font-family: Menlo,sans-serif;\n    font-size: 0.85rem;\n\">0</span></p>\n\n<p><strong>Explanation</strong><strong>:</strong> Since your score is <code>0</code> initially, you cannot play the token face-down. You also cannot play it face-up since your power (<code>50</code>) is less than <code>tokens[0]</code>&nbsp;(<code>100</code>).</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\" style=\"\n    border-color: var(--border-tertiary);\n    border-left-width: 2px;\n    color: var(--text-secondary);\n    font-size: .875rem;\n    margin-bottom: 1rem;\n    margin-top: 1rem;\n    overflow: visible;\n    padding-left: 1rem;\n\">\n<p><strong>Input:</strong> <span class=\"example-io\" style=\"\n    font-family: Menlo,sans-serif;\n    font-size: 0.85rem;\n\">tokens = [200,100], power = 150</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\" style=\"\n    font-family: Menlo,sans-serif;\n    font-size: 0.85rem;\n\">1</span></p>\n\n<p><strong>Explanation:</strong> Play token<em><sub>1</sub></em> (<code>100</code>) face-up, reducing your power to&nbsp;<code>50</code> and increasing your score to&nbsp;<code>1</code>.</p>\n\n<p>There is no need to play token<em><sub>0</sub></em>, since you cannot play it face-up to add to your score. The maximum score achievable is <code>1</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\" style=\"\n    border-color: var(--border-tertiary);\n    border-left-width: 2px;\n    color: var(--text-secondary);\n    font-size: .875rem;\n    margin-bottom: 1rem;\n    margin-top: 1rem;\n    overflow: visible;\n    padding-left: 1rem;\n\">\n<p><strong>Input:</strong> <span class=\"example-io\" style=\"\n    font-family: Menlo,sans-serif;\n    font-size: 0.85rem;\n\">tokens = [100,200,300,400], power = 200</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\" style=\"\n    font-family: Menlo,sans-serif;\n    font-size: 0.85rem;\n\">2</span></p>\n\n<p><strong>Explanation:</strong> Play the tokens in this order to get a score of <code>2</code>:</p>\n\n<ol>\n\t<li>Play token<em><sub>0</sub></em> (<code>100</code>) face-up, reducing power to <code>100</code> and increasing score to <code>1</code>.</li>\n\t<li>Play token<em><sub>3</sub></em> (<code>400</code>) face-down, increasing power to <code>500</code> and reducing score to <code>0</code>.</li>\n\t<li>Play token<em><sub>1</sub></em> (<code>200</code>) face-up, reducing power to <code>300</code> and increasing score to <code>1</code>.</li>\n\t<li>Play token<em><sub>2</sub></em> (<code>300</code>) face-up, reducing power to <code>0</code> and increasing score to <code>2</code>.</li>\n</ol>\n\n<p><span style=\"color: var(--text-secondary); font-size: 0.875rem;\">The maximum score achievable is </span><code style=\"color: var(--text-secondary); font-size: 0.875rem;\">2</code><span style=\"color: var(--text-secondary); font-size: 0.875rem;\">.</span></p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= tokens.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= tokens[i], power &lt; 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "令牌放置",
            "translatedContent": "<p>你的初始 <strong>能量</strong> 为 <code>power</code>，初始 <strong>分数</strong> 为&nbsp;<code>0</code>，只有一包令牌以整数数组&nbsp;<code>tokens</code>&nbsp;给出。其中 <code>tokens[i]</code> 是第 <code>i</code> 个令牌的值（下标从 0 开始）。</p>\n\n<p>你的目标是通过有策略地使用这些令牌以&nbsp;<strong>最大化</strong>&nbsp;总 <strong>分数</strong>。在一次行动中，你可以用两种方式中的一种来使用一个&nbsp;<strong>未被使用的</strong> 令牌（但不是对同一个令牌使用两种方式）：</p>\n\n<ul>\n\t<li><strong>朝上</strong>：如果你当前&nbsp;<strong>至少</strong> 有&nbsp;<code>tokens[i]</code>&nbsp;点 <strong>能量</strong> ，可以使用令牌 <code>i</code> ，失去&nbsp;<code>tokens[i]</code>&nbsp;点 <strong>能量</strong> ，并得到&nbsp;<code>1</code>&nbsp;<strong>分</strong> 。</li>\n\t<li><strong>朝下</strong>：如果你当前至少有&nbsp;<code>1</code>&nbsp;<strong>分 </strong>，可以使用令牌 <code>i</code> ，获得&nbsp;<code>tokens[i]</code> 点 <strong>能量</strong> ，并失去&nbsp;<code>1</code>&nbsp;<strong>分</strong> 。</li>\n</ul>\n\n<p>在使用 <strong>任意</strong> 数量的令牌后，返回我们可以得到的最大 <strong>分数</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<ol>\n</ol>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>tokens = [100], power = 50\n<strong>输出：</strong>0\n<strong>解释：</strong>因为你的初始分数为 <code>0，</code>无法使令牌朝下。你也不能使令牌朝上因为你的能量（<code>50</code>）比 <code>tokens[0]</code>&nbsp;少（<code>100</code>）。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>tokens = [200,100], power = 150\n<strong>输出：</strong>1\n<strong>解释：</strong>使令牌 1 正面朝上，能量变为 50，分数变为 1 。\n不必使用令牌 0，因为你无法使用它来提高分数。可得到的最大分数是 <code>1</code>。</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>tokens = [100,200,300,400], power = 200\n<strong>输出：</strong>2\n<strong>解释：</strong>按下面顺序使用令牌可以得到 2 分：\n1. 令牌 0 (<code>100</code>)正面朝上，能量变为 <code>100</code> ，分数变为 <code>1</code>\n2. 令牌 3 (<code>400</code>)正面朝下，能量变为 <code>500</code> ，分数变为 <code>0</code>\n3. 令牌 1 (<code>200</code>)正面朝上，能量变为 <code>300</code> ，分数变为 <code>1</code>\n4. 令牌 2 (<code>300</code>)正面朝上，能量变为 <code>0</code> ，分数变为 <code>2</code>\n\n可得的最大分数是 2。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= tokens.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= tokens[i],&nbsp;power &lt; 10<sup>4</sup></code></li>\n</ul>\n",
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