mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-09-04 06:51:41 +08:00
169 lines
20 KiB
JSON
169 lines
20 KiB
JSON
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"questionId": "1000146",
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"categoryTitle": "Algorithms",
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"boundTopicId": 411213,
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"title": "早餐组合",
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"titleSlug": "2vYnGI",
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"content": "English description is not available for the problem. Please switch to Chinese.",
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"translatedTitle": "早餐组合",
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"translatedContent": "小扣在秋日市集选择了一家早餐摊位,一维整型数组 `staple` 中记录了每种主食的价格,一维整型数组 `drinks` 中记录了每种饮料的价格。小扣的计划选择一份主食和一款饮料,且花费不超过 `x` 元。请返回小扣共有多少种购买方案。\r\n\r\n注意:答案需要以 `1e9 + 7 (1000000007)` 为底取模,如:计算初始结果为:`1000000008`,请返回 `1`\r\n\r\n**示例 1:**\r\n>输入:`staple = [10,20,5], drinks = [5,5,2], x = 15`\r\n>\r\n>输出:`6`\r\n>\r\n>解释:小扣有 6 种购买方案,所选主食与所选饮料在数组中对应的下标分别是:\r\n>第 1 种方案:staple[0] + drinks[0] = 10 + 5 = 15;\r\n>第 2 种方案:staple[0] + drinks[1] = 10 + 5 = 15;\r\n>第 3 种方案:staple[0] + drinks[2] = 10 + 2 = 12;\r\n>第 4 种方案:staple[2] + drinks[0] = 5 + 5 = 10;\r\n>第 5 种方案:staple[2] + drinks[1] = 5 + 5 = 10;\r\n>第 6 种方案:staple[2] + drinks[2] = 5 + 2 = 7。\r\n\r\n**示例 2:**\r\n>输入:`staple = [2,1,1], drinks = [8,9,5,1], x = 9`\r\n>\r\n>输出:`8`\r\n>\r\n>解释:小扣有 8 种购买方案,所选主食与所选饮料在数组中对应的下标分别是:\r\n>第 1 种方案:staple[0] + drinks[2] = 2 + 5 = 7;\r\n>第 2 种方案:staple[0] + drinks[3] = 2 + 1 = 3;\r\n>第 3 种方案:staple[1] + drinks[0] = 1 + 8 = 9;\r\n>第 4 种方案:staple[1] + drinks[2] = 1 + 5 = 6;\r\n>第 5 种方案:staple[1] + drinks[3] = 1 + 1 = 2;\r\n>第 6 种方案:staple[2] + drinks[0] = 1 + 8 = 9;\r\n>第 7 种方案:staple[2] + drinks[2] = 1 + 5 = 6;\r\n>第 8 种方案:staple[2] + drinks[3] = 1 + 1 = 2;\r\n\r\n**提示:**\r\n+ `1 <= staple.length <= 10^5`\r\n+ `1 <= drinks.length <= 10^5`\r\n+ `1 <= staple[i],drinks[i] <= 10^5`\r\n+ `1 <= x <= 2*10^5`",
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