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			34 lines
		
	
	
		
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			34 lines
		
	
	
		
			967 B
		
	
	
	
		
			HTML
		
	
	
	
	
	
给你一个链表的头节点 <code>head</code> 和一个整数 <code>val</code> ,请你删除链表中所有满足 <code>Node.val == val</code> 的节点,并返回 <strong>新的头节点</strong> 。
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<p> </p>
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<p><strong>示例 1:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2021/03/06/removelinked-list.jpg" style="width: 500px; height: 142px;" />
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<pre>
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<strong>输入:</strong>head = [1,2,6,3,4,5,6], val = 6
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<strong>输出:</strong>[1,2,3,4,5]
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</pre>
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<p><strong>示例 2:</strong></p>
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<pre>
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<strong>输入:</strong>head = [], val = 1
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<strong>输出:</strong>[]
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</pre>
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<p><strong>示例 3:</strong></p>
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<pre>
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<strong>输入:</strong>head = [7,7,7,7], val = 7
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<strong>输出:</strong>[]
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</pre>
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<p> </p>
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<p><strong>提示:</strong></p>
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<ul>
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	<li>列表中的节点数目在范围 <code>[0, 10<sup>4</sup>]</code> 内</li>
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	<li><code>1 <= Node.val <= 50</code></li>
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	<li><code>0 <= val <= 50</code></li>
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</ul>
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