leetcode-problemset/算法题（国外版）/minimum-number-of-steps-to-make-two-strings-anagram-ii.json

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            "title": "Minimum Number of Steps to Make Two Strings Anagram II",
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            "content": "<p>You are given two strings <code>s</code> and <code>t</code>. In one step, you can append <strong>any character</strong> to either <code>s</code> or <code>t</code>.</p>\n\n<p>Return <em>the minimum number of steps to make </em><code>s</code><em> and </em><code>t</code><em> <strong>anagrams</strong> of each other.</em></p>\n\n<p>An <strong>anagram</strong> of a string is a string that contains the same characters with a different (or the same) ordering.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;<strong><u>lee</u></strong>tco<u><strong>de</strong></u>&quot;, t = &quot;co<u><strong>a</strong></u>t<u><strong>s</strong></u>&quot;\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> \n- In 2 steps, we can append the letters in &quot;as&quot; onto s = &quot;leetcode&quot;, forming s = &quot;leetcode<strong><u>as</u></strong>&quot;.\n- In 5 steps, we can append the letters in &quot;leede&quot; onto t = &quot;coats&quot;, forming t = &quot;coats<u><strong>leede</strong></u>&quot;.\n&quot;leetcodeas&quot; and &quot;coatsleede&quot; are now anagrams of each other.\nWe used a total of 2 + 5 = 7 steps.\nIt can be shown that there is no way to make them anagrams of each other with less than 7 steps.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;night&quot;, t = &quot;thing&quot;\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The given strings are already anagrams of each other. Thus, we do not need any further steps.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, t.length &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li><code>s</code> and <code>t</code> consist of lowercase English letters.</li>\n</ul>\n",
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            "hints": [
                "Notice that for anagrams, the order of the letters is irrelevant.",
                "For each letter, we can count its frequency in s and t.",
                "For each letter, its contribution to the answer is the absolute difference between its frequency in s and t."
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