mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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162 lines
25 KiB
JSON
162 lines
25 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "235",
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"questionFrontendId": "235",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1543,
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"title": "Lowest Common Ancestor of a Binary Search Tree",
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"titleSlug": "lowest-common-ancestor-of-a-binary-search-tree",
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"content": "<p>Given a binary search tree (BST), find the lowest common ancestor (LCA) node of two given nodes in the BST.</p>\n\n<p>According to the <a href=\"https://en.wikipedia.org/wiki/Lowest_common_ancestor\" target=\"_blank\">definition of LCA on Wikipedia</a>: “The lowest common ancestor is defined between two nodes <code>p</code> and <code>q</code> as the lowest node in <code>T</code> that has both <code>p</code> and <code>q</code> as descendants (where we allow <strong>a node to be a descendant of itself</strong>).”</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2018/12/14/binarysearchtree_improved.png\" style=\"width: 200px; height: 190px;\" />\n<pre>\n<strong>Input:</strong> root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 8\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> The LCA of nodes 2 and 8 is 6.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2018/12/14/binarysearchtree_improved.png\" style=\"width: 200px; height: 190px;\" />\n<pre>\n<strong>Input:</strong> root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 4\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [2,1], p = 2, q = 1\n<strong>Output:</strong> 2\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[2, 10<sup>5</sup>]</code>.</li>\n\t<li><code>-10<sup>9</sup> <= Node.val <= 10<sup>9</sup></code></li>\n\t<li>All <code>Node.val</code> are <strong>unique</strong>.</li>\n\t<li><code>p != q</code></li>\n\t<li><code>p</code> and <code>q</code> will exist in the BST.</li>\n</ul>\n",
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"translatedTitle": "二叉搜索树的最近公共祖先",
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"translatedContent": "<p>给定一个二叉搜索树, 找到该树中两个指定节点的最近公共祖先。</p>\n\n<p><a href=\"https://baike.baidu.com/item/%E6%9C%80%E8%BF%91%E5%85%AC%E5%85%B1%E7%A5%96%E5%85%88/8918834?fr=aladdin\" target=\"_blank\">百度百科</a>中最近公共祖先的定义为：“对于有根树 T 的两个结点 p、q，最近公共祖先表示为一个结点 x，满足 x 是 p、q 的祖先且 x 的深度尽可能大（<strong>一个节点也可以是它自己的祖先</strong>）。”</p>\n\n<p>例如，给定如下二叉搜索树: root = [6,2,8,0,4,7,9,null,null,3,5]</p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/12/14/binarysearchtree_improved.png\" style=\"height: 190px; width: 200px;\"></p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong> root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 8\n<strong>输出:</strong> 6 \n<strong>解释: </strong>节点 <code>2 </code>和节点 <code>8 </code>的最近公共祖先是 <code>6。</code>\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong> root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 4\n<strong>输出:</strong> 2\n<strong>解释: </strong>节点 <code>2</code> 和节点 <code>4</code> 的最近公共祖先是 <code>2</code>, 因为根据定义最近公共祖先节点可以为节点本身。</pre>\n\n<p> </p>\n\n<p><strong>说明:</strong></p>\n\n<ul>\n\t<li>所有节点的值都是唯一的。</li>\n\t<li>p、q 为不同节点且均存在于给定的二叉搜索树中。</li>\n</ul>\n",
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"difficulty": "Medium",
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"name": "Depth-First Search",
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"slug": "depth-first-search",
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"translatedName": "深度优先搜索",
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"name": "Binary Search Tree",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode(int x) : val(x), left(NULL), right(NULL) {}\n * };\n */\n\nclass Solution {\npublic:\n TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {\n \n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode(int x) { val = x; }\n * }\n */\n\nclass Solution {\n public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {\n \n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, x):\n# self.val = x\n# self.left = None\n# self.right = None\n\nclass Solution(object):\n def lowestCommonAncestor(self, root, p, q):\n \"\"\"\n :type root: TreeNode\n :type p: TreeNode\n :type q: TreeNode\n :rtype: TreeNode\n \"\"\"\n ",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, x):\n# self.val = x\n# self.left = None\n# self.right = None\n\nclass Solution:\n def lowestCommonAncestor(self, root: 'TreeNode', p: 'TreeNode', q: 'TreeNode') -> 'TreeNode':\n ",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\nstruct TreeNode* lowestCommonAncestor(struct TreeNode* root, struct TreeNode* p, struct TreeNode* q) {\n \n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int x) { val = x; }\n * }\n */\n\npublic class Solution {\n public TreeNode LowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val) {\n * this.val = val;\n * this.left = this.right = null;\n * }\n */\n\n/**\n * @param {TreeNode} root\n * @param {TreeNode} p\n * @param {TreeNode} q\n * @return {TreeNode}\n */\nvar lowestCommonAncestor = function(root, p, q) {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction lowestCommonAncestor(root: TreeNode | null, p: TreeNode | null, q: TreeNode | null): TreeNode | null {\n\t\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($value) { $this->val = $value; }\n * }\n */\n\nclass Solution {\n /**\n * @param TreeNode $root\n * @param TreeNode $p\n * @param TreeNode $q\n * @return TreeNode\n */\n function lowestCommonAncestor($root, $p, $q) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init(_ val: Int) {\n * self.val = val\n * self.left = nil\n * self.right = nil\n * }\n * }\n */\n\nclass Solution {\n func lowestCommonAncestor(_ root: TreeNode?, _ p: TreeNode?, _ q: TreeNode?) -> TreeNode? {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int = 0) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\n\nclass Solution {\n fun lowestCommonAncestor(root: TreeNode?, p: TreeNode?, q: TreeNode?): TreeNode? {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\n\nfunc lowestCommonAncestor(root, p, q *TreeNode) *TreeNode {\n\t\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val)\n# @val = val\n# @left, @right = nil, nil\n# end\n# end\n\n# @param {TreeNode} root\n# @param {TreeNode} p\n# @param {TreeNode} q\n# @return {TreeNode}\ndef lowest_common_ancestor(root, p, q)\n \nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(var _value: Int) {\n * var value: Int = _value\n * var left: TreeNode = null\n * var right: TreeNode = null\n * }\n */\n\nobject Solution {\n def lowestCommonAncestor(root: TreeNode, p: TreeNode, q: TreeNode): TreeNode = {\n \n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n// \n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn lowest_common_ancestor(root: Option<Rc<RefCell<TreeNode>>>, p: Option<Rc<RefCell<TreeNode>>>, q: Option<Rc<RefCell<TreeNode>>>) -> Option<Rc<RefCell<TreeNode>>> {\n \n }\n}",
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