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leetcode-problemset/leetcode-cn/originData/remove-comments.json
2025-05-25 15:07:48 +08:00

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{
"data": {
"question": {
"questionId": "722",
"questionFrontendId": "722",
"categoryTitle": "Algorithms",
"boundTopicId": 1746,
"title": "Remove Comments",
"titleSlug": "remove-comments",
"content": "<p>Given a C++ program, remove comments from it. The program source is an array of strings <code>source</code> where <code>source[i]</code> is the <code>i<sup>th</sup></code> line of the source code. This represents the result of splitting the original source code string by the newline character <code>&#39;\\n&#39;</code>.</p>\n\n<p>In C++, there are two types of comments, line comments, and block comments.</p>\n\n<ul>\n\t<li>The string <code>&quot;//&quot;</code> denotes a line comment, which represents that it and the rest of the characters to the right of it in the same line should be ignored.</li>\n\t<li>The string <code>&quot;/*&quot;</code> denotes a block comment, which represents that all characters until the next (non-overlapping) occurrence of <code>&quot;*/&quot;</code> should be ignored. (Here, occurrences happen in reading order: line by line from left to right.) To be clear, the string <code>&quot;/*/&quot;</code> does not yet end the block comment, as the ending would be overlapping the beginning.</li>\n</ul>\n\n<p>The first effective comment takes precedence over others.</p>\n\n<ul>\n\t<li>For example, if the string <code>&quot;//&quot;</code> occurs in a block comment, it is ignored.</li>\n\t<li>Similarly, if the string <code>&quot;/*&quot;</code> occurs in a line or block comment, it is also ignored.</li>\n</ul>\n\n<p>If a certain line of code is empty after removing comments, you must not output that line: each string in the answer list will be non-empty.</p>\n\n<p>There will be no control characters, single quote, or double quote characters.</p>\n\n<ul>\n\t<li>For example, <code>source = &quot;string s = &quot;/* Not a comment. */&quot;;&quot;</code> will not be a test case.</li>\n</ul>\n\n<p>Also, nothing else such as defines or macros will interfere with the comments.</p>\n\n<p>It is guaranteed that every open block comment will eventually be closed, so <code>&quot;/*&quot;</code> outside of a line or block comment always starts a new comment.</p>\n\n<p>Finally, implicit newline characters can be deleted by block comments. Please see the examples below for details.</p>\n\n<p>After removing the comments from the source code, return <em>the source code in the same format</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> source = [&quot;/*Test program */&quot;, &quot;int main()&quot;, &quot;{ &quot;, &quot; // variable declaration &quot;, &quot;int a, b, c;&quot;, &quot;/* This is a test&quot;, &quot; multiline &quot;, &quot; comment for &quot;, &quot; testing */&quot;, &quot;a = b + c;&quot;, &quot;}&quot;]\n<strong>Output:</strong> [&quot;int main()&quot;,&quot;{ &quot;,&quot; &quot;,&quot;int a, b, c;&quot;,&quot;a = b + c;&quot;,&quot;}&quot;]\n<strong>Explanation:</strong> The line by line code is visualized as below:\n/*Test program */\nint main()\n{ \n // variable declaration \nint a, b, c;\n/* This is a test\n multiline \n comment for \n testing */\na = b + c;\n}\nThe string /* denotes a block comment, including line 1 and lines 6-9. The string // denotes line 4 as comments.\nThe line by line output code is visualized as below:\nint main()\n{ \n \nint a, b, c;\na = b + c;\n}\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> source = [&quot;a/*comment&quot;, &quot;line&quot;, &quot;more_comment*/b&quot;]\n<strong>Output:</strong> [&quot;ab&quot;]\n<strong>Explanation:</strong> The original source string is &quot;a/*comment\\nline\\nmore_comment*/b&quot;, where we have bolded the newline characters. After deletion, the implicit newline characters are deleted, leaving the string &quot;ab&quot;, which when delimited by newline characters becomes [&quot;ab&quot;].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= source.length &lt;= 100</code></li>\n\t<li><code>0 &lt;= source[i].length &lt;= 80</code></li>\n\t<li><code>source[i]</code> consists of printable <strong>ASCII</strong> characters.</li>\n\t<li>Every open block comment is eventually closed.</li>\n\t<li>There are no single-quote or&nbsp;double-quote in the input.</li>\n</ul>\n",
"translatedTitle": "删除注释",
"translatedContent": "<p>给一个 C++ 程序,删除程序中的注释。这个程序<code>source</code>是一个数组,其中<code>source[i]</code>表示第&nbsp;<code>i</code>&nbsp;行源码。&nbsp;这表示每行源码由 <code>'\\n'</code>&nbsp;分隔。</p>\n\n<p>在 C++ 中有两种注释风格,行内注释和块注释。</p>\n\n<ul>\n\t<li>字符串<code>//</code> 表示行注释,表示<code>//</code>和其右侧的其余字符应该被忽略。</li>\n\t<li>字符串<code>/*</code> 表示一个块注释,它表示直到下一个(非重叠)出现的<code>*/</code>之间的所有字符都应该被忽略。(阅读顺序为从左到右)非重叠是指,字符串<code>/*/</code>并没有结束块注释,因为注释的结尾与开头相重叠。</li>\n</ul>\n\n<p>第一个有效注释优先于其他注释。</p>\n\n<ul>\n\t<li>如果字符串<code>//</code>出现在块注释中会被忽略。</li>\n\t<li>同样,如果字符串<code>/*</code>出现在行或块注释中也会被忽略。</li>\n</ul>\n\n<p>如果一行在删除注释之后变为空字符串,那么<strong>不要</strong>输出该行。即,答案列表中的每个字符串都是非空的。</p>\n\n<p>样例中<strong>没有</strong>控制字符,单引号或双引号字符。</p>\n\n<ul>\n\t<li>比如,<code>source = \"string s = \"/* Not a comment. */\";\"</code> 不会出现在测试样例里。</li>\n</ul>\n\n<p>此外,没有其他内容(如定义或宏)会干扰注释。</p>\n\n<p>我们保证每一个块注释最终都会被闭合, 所以在行或块注释之外的<code>/*</code>总是开始新的注释。</p>\n\n<p>最后,隐式换行符<strong>可以</strong>通过块注释删除。 有关详细信息,请参阅下面的示例。</p>\n\n<p>从源代码中删除注释后,需要以相同的格式返回源代码。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1:</strong></p>\n\n<pre>\n<strong>输入:</strong> source = [\"/*Test program */\", \"int main()\", \"{ \", \" // variable declaration \", \"int a, b, c;\", \"/* This is a test\", \" multiline \", \" comment for \", \" testing */\", \"a = b + c;\", \"}\"]\n<strong>输出:</strong> [\"int main()\",\"{ \",\" \",\"int a, b, c;\",\"a = b + c;\",\"}\"]\n<strong>解释:</strong> 示例代码可以编排成这样:\n/*Test program */\nint main()\n{ \n // variable declaration \nint a, b, c;\n/* This is a test\n multiline \n comment for \n testing */\na = b + c;\n}\n第 1 行和第 6-9 行的字符串 /* 表示块注释。第 4 行的字符串 // 表示行注释。\n编排后: \nint main()\n{ \n \nint a, b, c;\na = b + c;\n}</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> source = [\"a/*comment\", \"line\", \"more_comment*/b\"]\n<strong>输出:</strong> [\"ab\"]\n<strong>解释:</strong> 原始的 source 字符串是 \"a/*comment<strong>\\n</strong>line<strong>\\n</strong>more_comment*/b\", 其中我们用粗体显示了换行符。删除注释后,隐含的换行符被删除,留下字符串 \"ab\" 用换行符分隔成数组时就是 [\"ab\"].\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= source.length &lt;= 100</code></li>\n\t<li><code>0 &lt;= source[i].length &lt;= 80</code></li>\n\t<li><code>source[i]</code>&nbsp;由可打印的 <strong>ASCII</strong> 字符组成。</li>\n\t<li>每个块注释都会被闭合。</li>\n\t<li>给定的源码中不会有单引号、双引号或其他控制字符。</li>\n</ul>\n<span style=\"display:block\"><span style=\"height:0px\"><span style=\"position:absolute\"><span style=\"top:0px\"><span style=\"left:-9999px\"><span style=\"opacity:0\"><span style=\"overflow:hidden\">&nbsp;</span></span></span></span></span></span></span>",
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