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leetcode-problemset/leetcode-cn/problem (English)/最大子数组和(English) [maximum-subarray].html
2022-03-29 12:43:11 +08:00

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<p>Given an integer array <code>nums</code>, find the contiguous subarray (containing at least one number) which has the largest sum and return <em>its sum</em>.</p>
<p>A <strong>subarray</strong> is a <strong>contiguous</strong> part of an array.</p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<pre>
<strong>Input:</strong> nums = [-2,1,-3,4,-1,2,1,-5,4]
<strong>Output:</strong> 6
<strong>Explanation:</strong> [4,-1,2,1] has the largest sum = 6.
</pre>
<p><strong>Example 2:</strong></p>
<pre>
<strong>Input:</strong> nums = [1]
<strong>Output:</strong> 1
</pre>
<p><strong>Example 3:</strong></p>
<pre>
<strong>Input:</strong> nums = [5,4,-1,7,8]
<strong>Output:</strong> 23
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>
</ul>
<p>&nbsp;</p>
<p><strong>Follow up:</strong> If you have figured out the <code>O(n)</code> solution, try coding another solution using the <strong>divide and conquer</strong> approach, which is more subtle.</p>