1
0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-01-11 02:58:13 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee
leetcode-problemset/leetcode-cn/problem (English)/寻找峰值(English) [find-peak-element].html
2022-03-29 12:43:11 +08:00

32 lines
1.2 KiB
HTML

<p>A peak element is an element that is strictly greater than its neighbors.</p>
<p>Given an integer array <code>nums</code>, find a peak element, and return its index. If&nbsp;the array contains multiple peaks, return the index to <strong>any of the peaks</strong>.</p>
<p>You may imagine that <code>nums[-1] = nums[n] = -&infin;</code>.</p>
<p>You must write an algorithm that runs in&nbsp;<code>O(log n)</code> time.</p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<pre>
<strong>Input:</strong> nums = [1,2,3,1]
<strong>Output:</strong> 2
<strong>Explanation:</strong> 3 is a peak element and your function should return the index number 2.</pre>
<p><strong>Example 2:</strong></p>
<pre>
<strong>Input:</strong> nums = [1,2,1,3,5,6,4]
<strong>Output:</strong> 5
<strong>Explanation:</strong> Your function can return either index number 1 where the peak element is 2, or index number 5 where the peak element is 6.</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= nums.length &lt;= 1000</code></li>
<li><code>-2<sup>31</sup> &lt;= nums[i] &lt;= 2<sup>31</sup> - 1</code></li>
<li><code>nums[i] != nums[i + 1]</code> for all valid <code>i</code>.</li>
</ul>