mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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180 lines
26 KiB
JSON
180 lines
26 KiB
JSON
{
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"questionId": "113",
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"questionFrontendId": "113",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1487,
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"title": "Path Sum II",
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"content": "<p>Given the <code>root</code> of a binary tree and an integer <code>targetSum</code>, return <em>all <strong>root-to-leaf</strong> paths where the sum of the node values in the path equals </em><code>targetSum</code><em>. Each path should be returned as a list of the node <strong>values</strong>, not node references</em>.</p>\n\n<p>A <strong>root-to-leaf</strong> path is a path starting from the root and ending at any leaf node. A <strong>leaf</strong> is a node with no children.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/18/pathsumii1.jpg\" style=\"width: 500px; height: 356px;\" />\n<pre>\n<strong>Input:</strong> root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22\n<strong>Output:</strong> [[5,4,11,2],[5,8,4,5]]\n<strong>Explanation:</strong> There are two paths whose sum equals targetSum:\n5 + 4 + 11 + 2 = 22\n5 + 8 + 4 + 5 = 22\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/18/pathsum2.jpg\" style=\"width: 212px; height: 181px;\" />\n<pre>\n<strong>Input:</strong> root = [1,2,3], targetSum = 5\n<strong>Output:</strong> []\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [1,2], targetSum = 0\n<strong>Output:</strong> []\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[0, 5000]</code>.</li>\n\t<li><code>-1000 <= Node.val <= 1000</code></li>\n\t<li><code>-1000 <= targetSum <= 1000</code></li>\n</ul>\n",
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"translatedTitle": "路径总和 II",
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"translatedContent": "<p>给你二叉树的根节点 <code>root</code> 和一个整数目标和 <code>targetSum</code> ，找出所有 <strong>从根节点到叶子节点</strong> 路径总和等于给定目标和的路径。</p>\n\n<p><strong>叶子节点</strong> 是指没有子节点的节点。</p>\n\n<div class=\"original__bRMd\">\n<div>\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/18/pathsumii1.jpg\" style=\"width: 500px; height: 356px;\" />\n<pre>\n<strong>输入：</strong>root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22\n<strong>输出：</strong>[[5,4,11,2],[5,8,4,5]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/18/pathsum2.jpg\" style=\"width: 212px; height: 181px;\" />\n<pre>\n<strong>输入：</strong>root = [1,2,3], targetSum = 5\n<strong>输出：</strong>[]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>root = [1,2], targetSum = 0\n<strong>输出：</strong>[]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点总数在范围 <code>[0, 5000]</code> 内</li>\n\t<li><code>-1000 <= Node.val <= 1000</code></li>\n\t<li><code>-1000 <= targetSum <= 1000</code></li>\n</ul>\n</div>\n</div>\n",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public IList<IList<int>> PathSum(TreeNode root, int targetSum) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} targetSum\n * @return {number[][]}\n */\nvar pathSum = function(root, targetSum) {\n\n};",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} target_sum\n# @return {Integer[][]}\ndef path_sum(root, target_sum)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func pathSum(_ root: TreeNode?, _ targetSum: Int) -> [[Int]] {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc pathSum(root *TreeNode, targetSum int) [][]int {\n\n}",
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