leetcode-problemset/leetcode-cn/originData/patching-array.json

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            "title": "Patching Array",
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            "content": "<p>Given a sorted integer array <code>nums</code> and an integer <code>n</code>, add/patch elements to the array such that any number in the range <code>[1, n]</code> inclusive can be formed by the sum of some elements in the array.</p>\n\n<p>Return <em>the minimum number of patches required</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3], n = 6\n<strong>Output:</strong> 1\nExplanation:\nCombinations of nums are [1], [3], [1,3], which form possible sums of: 1, 3, 4.\nNow if we add/patch 2 to nums, the combinations are: [1], [2], [3], [1,3], [2,3], [1,2,3].\nPossible sums are 1, 2, 3, 4, 5, 6, which now covers the range [1, 6].\nSo we only need 1 patch.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,5,10], n = 20\n<strong>Output:</strong> 2\nExplanation: The two patches can be [2, 4].\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,2], n = 5\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>nums</code> is sorted in <strong>ascending order</strong>.</li>\n\t<li><code>1 &lt;= n &lt;= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
            "translatedTitle": "按要求补齐数组",
            "translatedContent": "<p>给定一个已排序的正整数数组 <code>nums</code>&nbsp;<em>，</em>和一个正整数&nbsp;<code>n</code><em> 。</em>从&nbsp;<code>[1, n]</code>&nbsp;区间内选取任意个数字补充到&nbsp;nums&nbsp;中，使得&nbsp;<code>[1, n]</code>&nbsp;区间内的任何数字都可以用&nbsp;nums&nbsp;中某几个数字的和来表示。</p>\n\n<p>请返回 <em>满足上述要求的最少需要补充的数字个数</em>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1:</strong></p>\n\n<pre>\n<strong>输入: </strong>nums = <code>[1,3]</code>, n = <code>6</code>\n<strong>输出: </strong>1 \n<strong>解释:</strong>\n根据 nums&nbsp;里现有的组合&nbsp;<code>[1], [3], [1,3]</code>，可以得出&nbsp;<code>1, 3, 4</code>。\n现在如果我们将&nbsp;<code>2</code>&nbsp;添加到&nbsp;nums 中，&nbsp;组合变为: <code>[1], [2], [3], [1,3], [2,3], [1,2,3]</code>。\n其和可以表示数字&nbsp;<code>1, 2, 3, 4, 5, 6</code>，能够覆盖&nbsp;<code>[1, 6]</code>&nbsp;区间里所有的数。\n所以我们最少需要添加一个数字。</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入: </strong>nums = <code>[1,5,10]</code>, n = <code>20</code>\n<strong>输出:</strong> 2\n<strong>解释: </strong>我们需要添加&nbsp;<code>[2,4]</code>。\n</pre>\n\n<p><strong>示例&nbsp;3:</strong></p>\n\n<pre>\n<strong>输入: </strong>nums = <code>[1,2,2]</code>, n = <code>5</code>\n<strong>输出:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>nums</code>&nbsp;按 <strong>升序排列</strong></li>\n\t<li><code>1 &lt;= n &lt;= 2<sup>31</sup>&nbsp;- 1</code></li>\n</ul>\n",
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