mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 11:08:15 +08:00
197 lines
24 KiB
JSON
197 lines
24 KiB
JSON
{
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"question": {
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"questionId": "100177",
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"questionFrontendId": "面试题 04.05",
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"categoryTitle": "LCCI",
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"boundTopicId": 46212,
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"title": "Legal Binary Search Tree LCCI",
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"titleSlug": "legal-binary-search-tree-lcci",
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"content": "<p>Implement a function to check if a binary tree is a binary search tree.</p>\r\n\r\n<p><strong>Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong>\r\n 2\r\n / \\\r\n 1 3\r\n<strong>Output:</strong> true\r\n</pre>\r\n\r\n<p><strong>Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong>\r\n 5\r\n / \\\r\n 1 4\r\n / \\\r\n 3 6\r\n<strong>Output:</strong> false\r\n<strong>Explanation:</strong> Input: [5,1,4,null,null,3,6].\r\n the value of root node is 5, but its right child has value 4.</pre>\r\n",
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"translatedTitle": "合法二叉搜索树",
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"translatedContent": "<p>实现一个函数，检查一棵二叉树是否为二叉搜索树。</p><strong>示例 1:</strong><pre><strong>输入:</strong><br> 2<br> / \<br> 1 3<br><strong>输出:</strong> true<br></pre><strong>示例 2:</strong><pre><strong>输入:</strong><br> 5<br> / \<br> 1 4<br> / \<br> 3 6<br><strong>输出:</strong> false<br><strong>解释:</strong> 输入为: [5,1,4,null,null,3,6]。<br> 根节点的值为 5 ，但是其右子节点值为 4 。</pre>",
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"difficulty": "Medium",
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"likes": 71,
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"dislikes": 0,
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"isLiked": null,
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"similarQuestions": "[]",
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"contributors": [],
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"langToValidPlayground": "{\"cpp\": true, \"java\": true, \"python\": true, \"python3\": true, \"mysql\": false, \"mssql\": false, \"oraclesql\": false, \"c\": false, \"csharp\": false, \"javascript\": false, \"ruby\": false, \"bash\": false, \"swift\": false, \"golang\": false, \"scala\": false, \"html\": false, \"pythonml\": false, \"kotlin\": false, \"rust\": false, \"php\": false, \"typescript\": false, \"racket\": false, \"erlang\": false, \"elixir\": false}",
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"topicTags": [
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{
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"name": "Tree",
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"slug": "tree",
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"translatedName": "树",
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"__typename": "TopicTagNode"
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},
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{
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"name": "Depth-First Search",
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"slug": "depth-first-search",
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"translatedName": "深度优先搜索",
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"__typename": "TopicTagNode"
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},
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{
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"name": "Binary Search Tree",
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"slug": "binary-search-tree",
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"translatedName": "二叉搜索树",
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"__typename": "TopicTagNode"
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},
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{
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"name": "Binary Tree",
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"slug": "binary-tree",
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"translatedName": "二叉树",
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"__typename": "TopicTagNode"
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}
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],
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"lang": "C++",
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"langSlug": "cpp",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode(int x) : val(x), left(NULL), right(NULL) {}\n * };\n */\nclass Solution {\npublic:\n bool isValidBST(TreeNode* root) {\n\n }\n};",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "Java",
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"langSlug": "java",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode(int x) { val = x; }\n * }\n */\nclass Solution {\n public boolean isValidBST(TreeNode root) {\n\n }\n}",
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"__typename": "CodeSnippetNode"
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},
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"lang": "Python",
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"langSlug": "python",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, x):\n# self.val = x\n# self.left = None\n# self.right = None\n\nclass Solution(object):\n def isValidBST(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: bool\n \"\"\"",
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"__typename": "CodeSnippetNode"
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},
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"lang": "Python3",
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"langSlug": "python3",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, x):\n# self.val = x\n# self.left = None\n# self.right = None\n\nclass Solution:\n def isValidBST(self, root: TreeNode) -> bool:",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "C",
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"langSlug": "c",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\n\nbool isValidBST(struct TreeNode* root){\n\n}\n",
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{
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"lang": "C#",
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"langSlug": "csharp",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int x) { val = x; }\n * }\n */\npublic class Solution {\n public bool IsValidBST(TreeNode root) {\n\n }\n}",
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"__typename": "CodeSnippetNode"
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{
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"lang": "JavaScript",
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"langSlug": "javascript",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val) {\n * this.val = val;\n * this.left = this.right = null;\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {boolean}\n */\nvar isValidBST = function(root) {\n\n};",
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"__typename": "CodeSnippetNode"
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},
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"lang": "Ruby",
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"langSlug": "ruby",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val)\n# @val = val\n# @left, @right = nil, nil\n# end\n# end\n\n# @param {TreeNode} root\n# @return {Boolean}\ndef is_valid_bst(root)\n\nend",
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{
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"lang": "Swift",
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"langSlug": "swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init(_ val: Int) {\n * self.val = val\n * self.left = nil\n * self.right = nil\n * }\n * }\n */\nclass Solution {\n func isValidBST(_ root: TreeNode?) -> Bool {\n\n }\n}",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "Go",
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"langSlug": "golang",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc isValidBST(root *TreeNode) bool {\n\n}",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "Scala",
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"langSlug": "scala",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(var _value: Int) {\n * var value: Int = _value\n * var left: TreeNode = null\n * var right: TreeNode = null\n * }\n */\nobject Solution {\n def isValidBST(root: TreeNode): Boolean = {\n\n }\n}",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "Kotlin",
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"langSlug": "kotlin",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun isValidBST(root: TreeNode?): Boolean {\n\n }\n}",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "Rust",
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"langSlug": "rust",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n// \n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn is_valid_bst(root: Option<Rc<RefCell<TreeNode>>>) -> bool {\n\n }\n}",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "PHP",
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"langSlug": "php",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($value) { $this->val = $value; }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Boolean\n */\n function isValidBST($root) {\n\n }\n}",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "TypeScript",
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"langSlug": "typescript",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction isValidBST(root: TreeNode | null): boolean {\n\n};",
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},
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{
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"lang": "Racket",
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"langSlug": "racket",
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"code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (is-valid-bst root)\n (-> (or/c tree-node? #f) boolean?)\n\n )",
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"lang": "Erlang",
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"langSlug": "erlang",
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"code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec is_valid_bst(Root :: #tree_node{} | null) -> boolean().\nis_valid_bst(Root) ->\n .",
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},
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{
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"lang": "Elixir",
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"langSlug": "elixir",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec is_valid_bst(root :: TreeNode.t | nil) :: boolean\n def is_valid_bst(root) do\n\n end\nend",
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"__typename": "CodeSnippetNode"
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}
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"stats": "{\"totalAccepted\": \"30.3K\", \"totalSubmission\": \"85.9K\", \"totalAcceptedRaw\": 30268, \"totalSubmissionRaw\": 85898, \"acRate\": \"35.2%\"}",
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"hints": [
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"如果使用前序遍历来遍历树，元素的顺序是正确的，这是否表明树实际上是有序的？有重复元素会发生什么？如果允许重复元素，它们必须位于特定的一边（通常是左边）。",
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"作为一个二叉搜索树，并不是说每个节点都满足left.value <= current.value < right就够了。左边的每个节点必须小于当前节点，该节点还必须小于右边的所有节点。",
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"如果左边的每个节点必须小于或等于当前节点，那么这就等于左边最大的节点必须小于或等于当前节点。",
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"相比于根据leftTree.max和rightTree.min来验证当前节点的值，我们可以翻转逻辑吗？验证左子树的节点以确保其小于current.value。",
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"把checkBST函数当作一个递归函数，保证每个节点在允许范围内(最小, 最大)。首先，这个范围是无限的。当我们遍历左边，最小的是负无穷大，最大的是root.value。你能实现这个递归函数，并且随着遍历而适当调整这些范围吗？"
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],
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"sampleTestCase": "[2,1,3]",
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"metaData": "{\r\n \"name\": \"isValidBST\",\r\n \"params\": [\r\n {\r\n \"name\": \"root\",\r\n \"type\": \"TreeNode\"\r\n }\r\n ],\r\n \"return\": {\r\n \"type\": \"boolean\"\r\n }\r\n}",
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