mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 11:08:15 +08:00
185 lines
19 KiB
JSON
185 lines
19 KiB
JSON
{
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"question": {
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"questionId": "100322",
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"questionFrontendId": "剑指 Offer 57",
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"categoryTitle": "LCOF",
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"boundTopicId": 87857,
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"title": "和为s的两个数字 LCOF",
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"titleSlug": "he-wei-sde-liang-ge-shu-zi-lcof",
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"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\r\n",
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"translatedTitle": "和为s的两个数字",
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"translatedContent": "<p>输入一个递增排序的数组和一个数字s，在数组中查找两个数，使得它们的和正好是s。如果有多对数字的和等于s，则输出任意一对即可。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [2,7,11,15], target = 9\n<strong>输出：</strong>[2,7] 或者 [7,2]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [10,26,30,31,47,60], target = 40\n<strong>输出：</strong>[10,30] 或者 [30,10]\n</pre>\n\n<p> </p>\n\n<p><strong>限制：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10^5</code></li>\n\t<li><code>1 <= nums[i] <= 10^6</code></li>\n</ul>\n",
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"difficulty": "Easy",
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"likes": 171,
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"name": "Array",
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"translatedName": "数组",
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"name": "Two Pointers",
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"langSlug": "cpp",
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"code": "class Solution {\npublic:\n vector<int> twoSum(vector<int>& nums, int target) {\n\n }\n};",
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"code": "class Solution(object):\n def twoSum(self, nums, target):\n \"\"\"\n :type nums: List[int]\n :type target: int\n :rtype: List[int]\n \"\"\"",
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"code": "\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* twoSum(int* nums, int numsSize, int target, int* returnSize){\n\n}\n",
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"code": "# @param {Integer[]} nums\n# @param {Integer} target\n# @return {Integer[]}\ndef two_sum(nums, target)\n\nend",
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"sampleTestCase": "[2,7,11,15]\n9",
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