leetcode-problemset/leetcode-cn/originData/four-divisors.json

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            "categoryTitle": "Algorithms",
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            "title": "Four Divisors",
            "titleSlug": "four-divisors",
            "content": "<p>Given an integer array <code>nums</code>, return <em>the sum of divisors of the integers in that array that have exactly four divisors</em>. If there is no such integer in the array, return <code>0</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [21,4,7]\n<strong>Output:</strong> 32\n<strong>Explanation:</strong> \n21 has 4 divisors: 1, 3, 7, 21\n4 has 3 divisors: 1, 2, 4\n7 has 2 divisors: 1, 7\nThe answer is the sum of divisors of 21 only.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [21,21]\n<strong>Output:</strong> 64\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5]\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "四因数",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code>，请你返回该数组中恰有四个因数的这些整数的各因数之和。如果数组中不存在满足题意的整数，则返回 <code>0</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [21,4,7]\n<strong>输出：</strong>32\n<strong>解释：</strong>\n21 有 4 个因数：1, 3, 7, 21\n4 有 3 个因数：1, 2, 4\n7 有 2 个因数：1, 7\n答案仅为 21 的所有因数的和。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [21,21]\n<strong>输出:</strong> 64\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [1,2,3,4,5]\n<strong>输出:</strong> 0</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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