leetcode-problemset/leetcode-cn/originData/delete-the-middle-node-of-a-linked-list.json

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        "question": {
            "questionId": "2216",
            "questionFrontendId": "2095",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1134726,
            "title": "Delete the Middle Node of a Linked List",
            "titleSlug": "delete-the-middle-node-of-a-linked-list",
            "content": "<p>You are given the <code>head</code> of a linked list. <strong>Delete</strong> the <strong>middle node</strong>, and return <em>the</em> <code>head</code> <em>of the modified linked list</em>.</p>\n\n<p>The <strong>middle node</strong> of a linked list of size <code>n</code> is the <code>&lfloor;n / 2&rfloor;<sup>th</sup></code> node from the <b>start</b> using <strong>0-based indexing</strong>, where <code>&lfloor;x&rfloor;</code> denotes the largest integer less than or equal to <code>x</code>.</p>\n\n<ul>\n\t<li>For <code>n</code> = <code>1</code>, <code>2</code>, <code>3</code>, <code>4</code>, and <code>5</code>, the middle nodes are <code>0</code>, <code>1</code>, <code>1</code>, <code>2</code>, and <code>2</code>, respectively.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/11/16/eg1drawio.png\" style=\"width: 500px; height: 77px;\" />\n<pre>\n<strong>Input:</strong> head = [1,3,4,7,1,2,6]\n<strong>Output:</strong> [1,3,4,1,2,6]\n<strong>Explanation:</strong>\nThe above figure represents the given linked list. The indices of the nodes are written below.\nSince n = 7, node 3 with value 7 is the middle node, which is marked in red.\nWe return the new list after removing this node. \n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/11/16/eg2drawio.png\" style=\"width: 250px; height: 43px;\" />\n<pre>\n<strong>Input:</strong> head = [1,2,3,4]\n<strong>Output:</strong> [1,2,4]\n<strong>Explanation:</strong>\nThe above figure represents the given linked list.\nFor n = 4, node 2 with value 3 is the middle node, which is marked in red.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/11/16/eg3drawio.png\" style=\"width: 150px; height: 58px;\" />\n<pre>\n<strong>Input:</strong> head = [2,1]\n<strong>Output:</strong> [2]\n<strong>Explanation:</strong>\nThe above figure represents the given linked list.\nFor n = 2, node 1 with value 1 is the middle node, which is marked in red.\nNode 0 with value 2 is the only node remaining after removing node 1.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the list is in the range <code>[1, 10<sup>5</sup>]</code>.</li>\n\t<li><code>1 &lt;= Node.val &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "删除链表的中间节点",
            "translatedContent": "<p>给你一个链表的头节点 <code>head</code> 。<strong>删除</strong> 链表的 <strong>中间节点</strong> ，并返回修改后的链表的头节点 <code>head</code> 。</p>\n\n<p>长度为 <code>n</code> 链表的中间节点是从头数起第 <code>⌊n / 2⌋</code> 个节点（下标从 <strong>0</strong> 开始），其中 <code>⌊x⌋</code> 表示小于或等于 <code>x</code> 的最大整数。</p>\n\n<ul>\n\t<li>对于 <code>n</code> = <code>1</code>、<code>2</code>、<code>3</code>、<code>4</code> 和 <code>5</code> 的情况，中间节点的下标分别是 <code>0</code>、<code>1</code>、<code>1</code>、<code>2</code> 和 <code>2</code> 。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/11/16/eg1drawio.png\" style=\"width: 500px; height: 77px;\" /></p>\n\n<pre>\n<strong>输入：</strong>head = [1,3,4,7,1,2,6]\n<strong>输出：</strong>[1,3,4,1,2,6]\n<strong>解释：</strong>\n上图表示给出的链表。节点的下标分别标注在每个节点的下方。\n由于 n = 7 ，值为 7 的节点 3 是中间节点，用红色标注。\n返回结果为移除节点后的新链表。 \n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/11/16/eg2drawio.png\" style=\"width: 250px; height: 43px;\" /></p>\n\n<pre>\n<strong>输入：</strong>head = [1,2,3,4]\n<strong>输出：</strong>[1,2,4]\n<strong>解释：</strong>\n上图表示给出的链表。\n对于 n = 4 ，值为 3 的节点 2 是中间节点，用红色标注。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/11/16/eg3drawio.png\" style=\"width: 150px; height: 58px;\" /></p>\n\n<pre>\n<strong>输入：</strong>head = [2,1]\n<strong>输出：</strong>[2]\n<strong>解释：</strong>\n上图表示给出的链表。\n对于 n = 2 ，值为 1 的节点 1 是中间节点，用红色标注。\n值为 2 的节点 0 是移除节点 1 后剩下的唯一一个节点。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>链表中节点的数目在范围 <code>[1, 10<sup>5</sup>]</code> 内</li>\n\t<li><code>1 &lt;= Node.val &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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                    "name": "Linked List",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     ListNode *next;\n *     ListNode() : val(0), next(nullptr) {}\n *     ListNode(int x) : val(x), next(nullptr) {}\n *     ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n    ListNode* deleteMiddle(ListNode* head) {\n        \n    }\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     int val;\n *     ListNode next;\n *     ListNode() {}\n *     ListNode(int val) { this.val = val; }\n *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n    public ListNode deleteMiddle(ListNode head) {\n\n    }\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode(object):\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution(object):\n    def deleteMiddle(self, head):\n        \"\"\"\n        :type head: Optional[ListNode]\n        :rtype: Optional[ListNode]\n        \"\"\"",
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                    "code": "# Definition for singly-linked list.\n# class ListNode:\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution:\n    def deleteMiddle(self, head: Optional[ListNode]) -> Optional[ListNode]:",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     struct ListNode *next;\n * };\n */\n\n\nstruct ListNode* deleteMiddle(struct ListNode* head){\n\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public int val;\n *     public ListNode next;\n *     public ListNode(int val=0, ListNode next=null) {\n *         this.val = val;\n *         this.next = next;\n *     }\n * }\n */\npublic class Solution {\n    public ListNode DeleteMiddle(ListNode head) {\n\n    }\n}",
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                    "lang": "JavaScript",
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                    "code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {ListNode}\n */\nvar deleteMiddle = function(head) {\n\n};",
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                    "code": "# Definition for singly-linked list.\n# class ListNode\n#     attr_accessor :val, :next\n#     def initialize(val = 0, _next = nil)\n#         @val = val\n#         @next = _next\n#     end\n# end\n# @param {ListNode} head\n# @return {ListNode}\ndef delete_middle(head)\n\nend",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public var val: Int\n *     public var next: ListNode?\n *     public init() { self.val = 0; self.next = nil; }\n *     public init(_ val: Int) { self.val = val; self.next = nil; }\n *     public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n    func deleteMiddle(_ head: ListNode?) -> ListNode? {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode(_x: Int = 0, _next: ListNode = null) {\n *   var next: ListNode = _next\n *   var x: Int = _x\n * }\n */\nobject Solution {\n    def deleteMiddle(head: ListNode): ListNode = {\n\n    }\n}",
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                    "code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n *     var next: ListNode? = null\n * }\n */\nclass Solution {\n    fun deleteMiddle(head: ListNode?): ListNode? {\n\n    }\n}",
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                    "lang": "Rust",
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                    "code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n//   pub val: i32,\n//   pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n//   #[inline]\n//   fn new(val: i32) -> Self {\n//     ListNode {\n//       next: None,\n//       val\n//     }\n//   }\n// }\nimpl Solution {\n    pub fn delete_middle(head: Option<Box<ListNode>>) -> Option<Box<ListNode>> {\n\n    }\n}",
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                    "lang": "PHP",
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                    "code": "/**\n * Definition for a singly-linked list.\n * class ListNode {\n *     public $val = 0;\n *     public $next = null;\n *     function __construct($val = 0, $next = null) {\n *         $this->val = $val;\n *         $this->next = $next;\n *     }\n * }\n */\nclass Solution {\n\n    /**\n     * @param ListNode $head\n     * @return ListNode\n     */\n    function deleteMiddle($head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *     val: number\n *     next: ListNode | null\n *     constructor(val?: number, next?: ListNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.next = (next===undefined ? null : next)\n *     }\n * }\n */\n\nfunction deleteMiddle(head: ListNode | null): ListNode | null {\n\n};",
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                    "lang": "Racket",
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                    "code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n  (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n  (list-node val #f))\n\n|#\n\n(define/contract (delete-middle head)\n  (-> (or/c list-node? #f) (or/c list-node? #f))\n\n  )",
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                    "lang": "Erlang",
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                    "code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%%                     next = null :: 'null' | #list_node{}}).\n\n-spec delete_middle(Head :: #list_node{} | null) -> #list_node{} | null.\ndelete_middle(Head) ->\n  .",
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                    "code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           next: ListNode.t() | nil\n#         }\n#   defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n  @spec delete_middle(head :: ListNode.t | nil) :: ListNode.t | nil\n  def delete_middle(head) do\n\n  end\nend",
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                "If a point with a speed s moves n units in a given time, a point with speed 2 * s will move 2 * n units at the same time. Can you use this to find the middle node of a linked list?",
                "If you are given the middle node, the node before it, and the node after it, how can you modify the linked list?"
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href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\\" target=\\\"_blank\\\"> datastructures-js\\/queue<\\/a>\\u3002<\\/p>\"],\"ruby\":[\"Ruby\",\"<p>\\u4f7f\\u7528<code>Ruby 3.1<\\/code>\\u6267\\u884c<\\/p>\\r\\n\\r\\n<p>\\u4e00\\u4e9b\\u5e38\\u7528\\u7684\\u6570\\u636e\\u7ed3\\u6784\\u5df2\\u5728 Algorithms \\u6a21\\u5757\\u4e2d\\u63d0\\u4f9b\\uff1ahttps:\\/\\/www.rubydoc.info\\/github\\/kanwei\\/algorithms\\/Algorithms<\\/p>\"],\"swift\":[\"Swift\",\"<p>\\u7248\\u672c\\uff1a<code>Swift 5.5.2<\\/code><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u901a\\u5e38\\u4fdd\\u8bc1\\u66f4\\u65b0\\u5230 <a href=\\\"https:\\/\\/swift.org\\/download\\/\\\" target=\\\"_blank\\\">Apple\\u653e\\u51fa\\u7684\\u6700\\u65b0\\u7248Swift<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u53d1\\u73b0Swift\\u4e0d\\u662f\\u6700\\u65b0\\u7248\\u7684\\uff0c\\u8bf7\\u8054\\u7cfb\\u6211\\u4eec\\uff01\\u6211\\u4eec\\u5c06\\u5c3d\\u5feb\\u66f4\\u65b0\\u3002<\\/p>\"],\"golang\":[\"Go\",\"<p>\\u7248\\u672c\\uff1a<code>Go 1.17<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 2.13<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.3.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 4.5.4<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2020<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.3<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 24.2\"],\"elixir\":[\"Elixir\",\"Elixir 1.13.0 with Erlang\\/OTP 24.2\"]}",
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