mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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178 lines
20 KiB
JSON
178 lines
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"title": "Complex Number Multiplication",
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"content": "<p>A <a href=\"https://en.wikipedia.org/wiki/Complex_number\" target=\"_blank\">complex number</a> can be represented as a string on the form <code>"<strong>real</strong>+<strong>imaginary</strong>i"</code> where:</p>\n\n<ul>\n\t<li><code>real</code> is the real part and is an integer in the range <code>[-100, 100]</code>.</li>\n\t<li><code>imaginary</code> is the imaginary part and is an integer in the range <code>[-100, 100]</code>.</li>\n\t<li><code>i<sup>2</sup> == -1</code>.</li>\n</ul>\n\n<p>Given two complex numbers <code>num1</code> and <code>num2</code> as strings, return <em>a string of the complex number that represents their multiplications</em>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num1 = "1+1i", num2 = "1+1i"\n<strong>Output:</strong> "0+2i"\n<strong>Explanation:</strong> (1 + i) * (1 + i) = 1 + i2 + 2 * i = 2i, and you need convert it to the form of 0+2i.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num1 = "1+-1i", num2 = "1+-1i"\n<strong>Output:</strong> "0+-2i"\n<strong>Explanation:</strong> (1 - i) * (1 - i) = 1 + i2 - 2 * i = -2i, and you need convert it to the form of 0+-2i.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>num1</code> and <code>num2</code> are valid complex numbers.</li>\n</ul>\n",
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"translatedContent": "<p><a href=\"https://baike.baidu.com/item/%E5%A4%8D%E6%95%B0/254365?fr=aladdin\" target=\"_blank\">复数</a> 可以用字符串表示，遵循 <code>\"<strong>实部</strong>+<strong>虚部</strong>i\"</code> 的形式，并满足下述条件：</p>\n\n<ul>\n\t<li><code>实部</code> 是一个整数，取值范围是 <code>[-100, 100]</code></li>\n\t<li><code>虚部</code> 也是一个整数，取值范围是 <code>[-100, 100]</code></li>\n\t<li><code>i<sup>2</sup> == -1</code></li>\n</ul>\n\n<p>给你两个字符串表示的复数 <code>num1</code> 和 <code>num2</code> ，请你遵循复数表示形式，返回表示它们乘积的字符串。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>num1 = \"1+1i\", num2 = \"1+1i\"\n<strong>输出：</strong>\"0+2i\"\n<strong>解释：</strong>(1 + i) * (1 + i) = 1 + i2 + 2 * i = 2i ，你需要将它转换为 0+2i 的形式。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>num1 = \"1+-1i\", num2 = \"1+-1i\"\n<strong>输出：</strong>\"0+-2i\"\n<strong>解释：</strong>(1 - i) * (1 - i) = 1 + i2 - 2 * i = -2i ，你需要将它转换为 0+-2i 的形式。 \n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>num1</code> 和 <code>num2</code> 都是有效的复数表示。</li>\n</ul>\n",
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