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leetcode-problemset/leetcode-cn/originData/bitwise-ors-of-subarrays.json
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"questionFrontendId": "898",
"categoryTitle": "Algorithms",
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"title": "Bitwise ORs of Subarrays",
"titleSlug": "bitwise-ors-of-subarrays",
"content": "<p>We have an array <code>arr</code> of non-negative integers.</p>\n\n<p>For every (contiguous) subarray <code>sub = [arr[i], arr[i + 1], ..., arr[j]]</code> (with <code>i &lt;= j</code>), we take the bitwise OR of all the elements in <code>sub</code>, obtaining a result <code>arr[i] | arr[i + 1] | ... | arr[j]</code>.</p>\n\n<p>Return the number of possible results. Results that occur more than once are only counted once in the final answer</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [0]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> There is only one possible result: 0.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [1,1,2]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The possible subarrays are [1], [1], [2], [1, 1], [1, 2], [1, 1, 2].\nThese yield the results 1, 1, 2, 1, 3, 3.\nThere are 3 unique values, so the answer is 3.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [1,2,4]\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> The possible results are 1, 2, 3, 4, 6, and 7.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= nums[i]&nbsp;&lt;= 10<sup>9</sup></code></li>\n</ul>\n",
"translatedTitle": "子数组按位或操作",
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