leetcode-problemset/leetcode-cn/originData/as-far-from-land-as-possible.json

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            "title": "As Far from Land as Possible",
            "titleSlug": "as-far-from-land-as-possible",
            "content": "<p>Given an <code>n x n</code> <code>grid</code>&nbsp;containing only values <code>0</code> and <code>1</code>, where&nbsp;<code>0</code> represents water&nbsp;and <code>1</code> represents land, find a water cell such that its distance to the nearest land cell is maximized, and return the distance.&nbsp;If no land or water exists in the grid, return <code>-1</code>.</p>\n\n<p>The distance used in this problem is the Manhattan distance:&nbsp;the distance between two cells <code>(x0, y0)</code> and <code>(x1, y1)</code> is <code>|x0 - x1| + |y0 - y1|</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/05/03/1336_ex1.JPG\" style=\"width: 185px; height: 87px;\" />\n<pre>\n<strong>Input:</strong> grid = [[1,0,1],[0,0,0],[1,0,1]]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The cell (1, 1) is as far as possible from all the land with distance 2.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/05/03/1336_ex2.JPG\" style=\"width: 184px; height: 87px;\" />\n<pre>\n<strong>Input:</strong> grid = [[1,0,0],[0,0,0],[0,0,0]]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The cell (2, 2) is as far as possible from all the land with distance 4.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>1 &lt;= n&nbsp;&lt;= 100</code></li>\n\t<li><code>grid[i][j]</code>&nbsp;is <code>0</code> or <code>1</code></li>\n</ul>\n",
            "translatedTitle": "地图分析",
            "translatedContent": "<p>你现在手里有一份大小为<meta charset=\"UTF-8\" />&nbsp;<code>n x n</code>&nbsp;的 网格 <code>grid</code>，上面的每个 单元格 都用&nbsp;<code>0</code>&nbsp;和&nbsp;<code>1</code>&nbsp;标记好了。其中&nbsp;<code>0</code>&nbsp;代表海洋，<code>1</code>&nbsp;代表陆地。</p>\n\n<p>请你找出一个海洋单元格，这个海洋单元格到离它最近的陆地单元格的距离是最大的，并返回该距离。如果网格上只有陆地或者海洋，请返回&nbsp;<code>-1</code>。</p>\n\n<p>我们这里说的距离是「曼哈顿距离」（&nbsp;Manhattan Distance）：<code>(x0, y0)</code> 和&nbsp;<code>(x1, y1)</code>&nbsp;这两个单元格之间的距离是&nbsp;<code>|x0 - x1| + |y0 - y1|</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/08/17/1336_ex1.jpeg\" /></strong></p>\n\n<pre>\n<strong>输入：</strong>grid = [[1,0,1],[0,0,0],[1,0,1]]\n<strong>输出：</strong>2\n<strong>解释： </strong>\n海洋单元格 (1, 1) 和所有陆地单元格之间的距离都达到最大，最大距离为 2。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/08/17/1336_ex2.jpeg\" /></strong></p>\n\n<pre>\n<strong>输入：</strong>grid = [[1,0,0],[0,0,0],[0,0,0]]\n<strong>输出：</strong>4\n<strong>解释： </strong>\n海洋单元格 (2, 2) 和所有陆地单元格之间的距离都达到最大，最大距离为 4。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<p><meta charset=\"UTF-8\" /></p>\n\n<ul>\n\t<li><code>n == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>1 &lt;= n&nbsp;&lt;= 100</code></li>\n\t<li><code>grid[i][j]</code>&nbsp;不是&nbsp;<code>0</code>&nbsp;就是&nbsp;<code>1</code></li>\n</ul>\n",
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            "hints": [
                "Can you think of this problem in a backwards way ?",
                "Imagine expanding outward from each land cell. What kind of search does that ?",
                "Use BFS starting from all land cells in the same time.",
                "When do you reach the furthest water cell?"
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