leetcode-problemset/leetcode-cn/originData/button-with-longest-push-time.json

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        "question": {
            "questionId": "3632",
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            "categoryTitle": "Algorithms",
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            "title": "Button with Longest Push Time",
            "titleSlug": "button-with-longest-push-time",
            "content": "<p>You are given a 2D array <code>events</code> which represents a sequence of events where a child pushes a series of buttons on a keyboard.</p>\n\n<p>Each <code>events[i] = [index<sub>i</sub>, time<sub>i</sub>]</code> indicates that the button at index <code>index<sub>i</sub></code> was pressed at time <code>time<sub>i</sub></code>.</p>\n\n<ul>\n\t<li>The array is <strong>sorted</strong> in increasing order of <code>time</code>.</li>\n\t<li>The time taken to press a button is the difference in time between consecutive button presses. The time for the first button is simply the time at which it was pressed.</li>\n</ul>\n\n<p>Return the <code>index</code> of the button that took the <strong>longest</strong> time to push. If multiple buttons have the same longest time, return the button with the <strong>smallest</strong> <code>index</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">events = [[1,2],[2,5],[3,9],[1,15]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Button with index 1 is pressed at time 2.</li>\n\t<li>Button with index 2 is pressed at time 5, so it took <code>5 - 2 = 3</code> units of time.</li>\n\t<li>Button with index 3 is pressed at time 9, so it took <code>9 - 5 = 4</code> units of time.</li>\n\t<li>Button with index 1 is pressed again at time 15, so it took <code>15 - 9 = 6</code> units of time.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">events = [[10,5],[1,7]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">10</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Button with index 10 is pressed at time 5.</li>\n\t<li>Button with index 1 is pressed at time 7, so it took <code>7 - 5 = 2</code> units of time.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= events.length &lt;= 1000</code></li>\n\t<li><code>events[i] == [index<sub>i</sub>, time<sub>i</sub>]</code></li>\n\t<li><code>1 &lt;= index<sub>i</sub>, time<sub>i</sub> &lt;= 10<sup>5</sup></code></li>\n\t<li>The input is generated such that <code>events</code> is sorted in increasing order of <code>time<sub>i</sub></code>.</li>\n</ul>\n",
            "translatedTitle": "按下时间最长的按钮",
            "translatedContent": "<p>给你一个二维数组 <code>events</code>，表示孩子在键盘上按下一系列按钮触发的按钮事件。</p>\n\n<p>每个 <code>events[i] = [index<sub>i</sub>, time<sub>i</sub>]</code> 表示在时间 <code>time<sub>i</sub></code> 时，按下了下标为 <code>index<sub>i</sub></code> 的按钮。</p>\n\n<ul>\n\t<li>数组按照 <code>time</code> 的递增顺序<strong>排序</strong>。</li>\n\t<li>按下一个按钮所需的时间是连续两次按钮按下的时间差。按下第一个按钮所需的时间就是其时间戳。</li>\n</ul>\n\n<p>返回按下时间&nbsp;<strong>最长&nbsp;</strong>的按钮的 <code>index</code>。如果有多个按钮的按下时间相同，则返回 <code>index</code> 最小的按钮。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">events = [[1,2],[2,5],[3,9],[1,15]]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>下标为 1 的按钮在时间 2 被按下。</li>\n\t<li>下标为 2 的按钮在时间 5 被按下，因此按下时间为 <code>5 - 2 = 3</code>。</li>\n\t<li>下标为 3 的按钮在时间 9 被按下，因此按下时间为 <code>9 - 5 = 4</code>。</li>\n\t<li>下标为 1 的按钮再次在时间 15 被按下，因此按下时间为 <code>15 - 9 = 6</code>。</li>\n</ul>\n\n<p>最终，下标为 1 的按钮按下时间最长，为 6。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">events = [[10,5],[1,7]]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">10</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>下标为 10 的按钮在时间 5 被按下。</li>\n\t<li>下标为 1 的按钮在时间 7 被按下，因此按下时间为 <code>7 - 5 = 2</code>。</li>\n</ul>\n\n<p>最终，下标为 10 的按钮按下时间最长，为 5。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= events.length &lt;= 1000</code></li>\n\t<li><code>events[i] == [index<sub>i</sub>, time<sub>i</sub>]</code></li>\n\t<li><code>1 &lt;= index<sub>i</sub>, time<sub>i</sub> &lt;= 10<sup>5</sup></code></li>\n\t<li>输入保证数组 <code>events</code> 按照 <code>time<sub>i</sub></code> 的递增顺序排序。</li>\n</ul>\n",
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