leetcode-problemset/leetcode-cn/originData/trapping-rain-water-ii.json

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            "title": "Trapping Rain Water II",
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            "content": "<p>Given an <code>m x n</code> integer matrix <code>heightMap</code> representing the height of each unit cell in a 2D elevation map, return <em>the volume of water it can trap after raining</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/08/trap1-3d.jpg\" style=\"width: 361px; height: 321px;\" />\n<pre>\n<strong>Input:</strong> heightMap = [[1,4,3,1,3,2],[3,2,1,3,2,4],[2,3,3,2,3,1]]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> After the rain, water is trapped between the blocks.\nWe have two small ponds 1 and 3 units trapped.\nThe total volume of water trapped is 4.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/08/trap2-3d.jpg\" style=\"width: 401px; height: 321px;\" />\n<pre>\n<strong>Input:</strong> heightMap = [[3,3,3,3,3],[3,2,2,2,3],[3,2,1,2,3],[3,2,2,2,3],[3,3,3,3,3]]\n<strong>Output:</strong> 10\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == heightMap.length</code></li>\n\t<li><code>n == heightMap[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 200</code></li>\n\t<li><code>0 &lt;= heightMap[i][j] &lt;= 2 * 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "接雨水 II",
            "translatedContent": "<p>给你一个&nbsp;<code>m x n</code>&nbsp;的矩阵，其中的值均为非负整数，代表二维高度图每个单元的高度，请计算图中形状最多能接多少体积的雨水。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/08/trap1-3d.jpg\" /></p>\n\n<pre>\n<strong>输入:</strong> heightMap = [[1,4,3,1,3,2],[3,2,1,3,2,4],[2,3,3,2,3,1]]\n<strong>输出:</strong> 4\n<strong>解释:</strong> 下雨后，雨水将会被上图蓝色的方块中。总的接雨水量为1+2+1=4。\n</pre>\n\n<p><strong>示例&nbsp;2:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/08/trap2-3d.jpg\" /></p>\n\n<pre>\n<strong>输入:</strong> heightMap = [[3,3,3,3,3],[3,2,2,2,3],[3,2,1,2,3],[3,2,2,2,3],[3,3,3,3,3]]\n<strong>输出:</strong> 10\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>m == heightMap.length</code></li>\n\t<li><code>n == heightMap[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 200</code></li>\n\t<li><code>0 &lt;= heightMap[i][j] &lt;= 2 * 10<sup>4</sup></code></li>\n</ul>\n\n<p>&nbsp;</p>\n",
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