mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 11:08:15 +08:00
174 lines
20 KiB
JSON
174 lines
20 KiB
JSON
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"questionId": "74",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1319,
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"title": "Search a 2D Matrix",
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"titleSlug": "search-a-2d-matrix",
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"content": "<p>Write an efficient algorithm that searches for a value <code>target</code> in an <code>m x n</code> integer matrix <code>matrix</code>. This matrix has the following properties:</p>\n\n<ul>\n\t<li>Integers in each row are sorted from left to right.</li>\n\t<li>The first integer of each row is greater than the last integer of the previous row.</li>\n</ul>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/05/mat.jpg\" style=\"width: 322px; height: 242px;\" />\n<pre>\n<strong>Input:</strong> matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 3\n<strong>Output:</strong> true\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/05/mat2.jpg\" style=\"width: 322px; height: 242px;\" />\n<pre>\n<strong>Input:</strong> matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 13\n<strong>Output:</strong> false\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == matrix.length</code></li>\n\t<li><code>n == matrix[i].length</code></li>\n\t<li><code>1 <= m, n <= 100</code></li>\n\t<li><code>-10<sup>4</sup> <= matrix[i][j], target <= 10<sup>4</sup></code></li>\n</ul>\n",
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"translatedTitle": "搜索二维矩阵",
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"translatedContent": "<p>编写一个高效的算法来判断 <code>m x n</code> 矩阵中，是否存在一个目标值。该矩阵具有如下特性：</p>\n\n<ul>\n\t<li>每行中的整数从左到右按升序排列。</li>\n\t<li>每行的第一个整数大于前一行的最后一个整数。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/05/mat.jpg\" style=\"width: 322px; height: 242px;\" />\n<pre>\n<strong>输入：</strong>matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 3\n<strong>输出：</strong>true\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/11/25/mat2.jpg\" style=\"width: 322px; height: 242px;\" />\n<pre>\n<strong>输入：</strong>matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 13\n<strong>输出：</strong>false\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == matrix.length</code></li>\n\t<li><code>n == matrix[i].length</code></li>\n\t<li><code>1 <= m, n <= 100</code></li>\n\t<li><code>-10<sup>4</sup> <= matrix[i][j], target <= 10<sup>4</sup></code></li>\n</ul>\n",
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"difficulty": "Medium",
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"code": "# @param {Integer[][]} matrix\n# @param {Integer} target\n# @return {Boolean}\ndef search_matrix(matrix, target)\n\nend",
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