leetcode-problemset/leetcode-cn/originData/maximum-product-difference-between-two-pairs.json

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            "title": "Maximum Product Difference Between Two Pairs",
            "titleSlug": "maximum-product-difference-between-two-pairs",
            "content": "<p>The <strong>product difference</strong> between two pairs <code>(a, b)</code> and <code>(c, d)</code> is defined as <code>(a * b) - (c * d)</code>.</p>\r\n\r\n<ul>\r\n\t<li>For example, the product difference between <code>(5, 6)</code> and <code>(2, 7)</code> is <code>(5 * 6) - (2 * 7) = 16</code>.</li>\r\n</ul>\r\n\r\n<p>Given an integer array <code>nums</code>, choose four <strong>distinct</strong> indices <code>w</code>, <code>x</code>, <code>y</code>, and <code>z</code> such that the <strong>product difference</strong> between pairs <code>(nums[w], nums[x])</code> and <code>(nums[y], nums[z])</code> is <strong>maximized</strong>.</p>\r\n\r\n<p>Return <em>the <strong>maximum</strong> such product difference</em>.</p>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong>Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> nums = [5,6,2,7,4]\r\n<strong>Output:</strong> 34\r\n<strong>Explanation:</strong> We can choose indices 1 and 3 for the first pair (6, 7) and indices 2 and 4 for the second pair (2, 4).\r\nThe product difference is (6 * 7) - (2 * 4) = 34.\r\n</pre>\r\n\r\n<p><strong>Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> nums = [4,2,5,9,7,4,8]\r\n<strong>Output:</strong> 64\r\n<strong>Explanation:</strong> We can choose indices 3 and 6 for the first pair (9, 8) and indices 1 and 5 for the second pair (2, 4).\r\nThe product difference is (9 * 8) - (2 * 4) = 64.\r\n</pre>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong>Constraints:</strong></p>\r\n\r\n<ul>\r\n\t<li><code>4 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\r\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\r\n</ul>",
            "translatedTitle": "两个数对之间的最大乘积差",
            "translatedContent": "<p>两个数对 <code>(a, b)</code> 和 <code>(c, d)</code> 之间的 <strong>乘积差</strong> 定义为 <code>(a * b) - (c * d)</code> 。</p>\n\n<ul>\n\t<li>例如，<code>(5, 6)</code> 和 <code>(2, 7)</code> 之间的乘积差是 <code>(5 * 6) - (2 * 7) = 16</code> 。</li>\n</ul>\n\n<p>给你一个整数数组 <code>nums</code> ，选出四个 <strong>不同的</strong> 下标 <code>w</code>、<code>x</code>、<code>y</code> 和 <code>z</code> ，使数对 <code>(nums[w], nums[x])</code> 和 <code>(nums[y], nums[z])</code> 之间的 <strong>乘积差</strong> 取到 <strong>最大值</strong> 。</p>\n\n<p>返回以这种方式取得的乘积差中的 <strong>最大值</strong> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [5,6,2,7,4]\n<strong>输出：</strong>34\n<strong>解释：</strong>可以选出下标为 1 和 3 的元素构成第一个数对 (6, 7) 以及下标 2 和 4 构成第二个数对 (2, 4)\n乘积差是 (6 * 7) - (2 * 4) = 34\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [4,2,5,9,7,4,8]\n<strong>输出：</strong>64\n<strong>解释：</strong>可以选出下标为 3 和 6 的元素构成第一个数对 (9, 8) 以及下标 1 和 5 构成第二个数对 (2, 4)\n乘积差是 (9 * 8) - (2 * 4) = 64\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>4 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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