leetcode-problemset/leetcode-cn/originData/intersection-of-two-arrays-ii.json

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            "title": "Intersection of Two Arrays II",
            "titleSlug": "intersection-of-two-arrays-ii",
            "content": "<p>Given two integer arrays <code>nums1</code> and <code>nums2</code>, return <em>an array of their intersection</em>. Each element in the result must appear as many times as it shows in both arrays and you may return the result in <strong>any order</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,2,2,1], nums2 = [2,2]\n<strong>Output:</strong> [2,2]\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [4,9,5], nums2 = [9,4,9,8,4]\n<strong>Output:</strong> [4,9]\n<strong>Explanation:</strong> [9,4] is also accepted.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums1.length, nums2.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums1[i], nums2[i] &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong></p>\n\n<ul>\n\t<li>What if the given array is already sorted? How would you optimize your algorithm?</li>\n\t<li>What if <code>nums1</code>&#39;s size is small compared to <code>nums2</code>&#39;s size? Which algorithm is better?</li>\n\t<li>What if elements of <code>nums2</code> are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?</li>\n</ul>\n",
            "translatedTitle": "两个数组的交集 II",
            "translatedContent": "<p>给你两个整数数组&nbsp;<code>nums1</code> 和 <code>nums2</code> ，请你以数组形式返回两数组的交集。返回结果中每个元素出现的次数，应与元素在两个数组中都出现的次数一致（如果出现次数不一致，则考虑取较小值）。可以不考虑输出结果的顺序。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [1,2,2,1], nums2 = [2,2]\n<strong>输出：</strong>[2,2]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [4,9,5], nums2 = [9,4,9,8,4]\n<strong>输出：</strong>[4,9]</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums1.length, nums2.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums1[i], nums2[i] &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong><strong>进阶</strong>：</strong></p>\n\n<ul>\n\t<li>如果给定的数组已经排好序呢？你将如何优化你的算法？</li>\n\t<li>如果&nbsp;<code>nums1</code><em>&nbsp;</em>的大小比&nbsp;<code>nums2</code> 小，哪种方法更优？</li>\n\t<li>如果&nbsp;<code>nums2</code><em>&nbsp;</em>的元素存储在磁盘上，内存是有限的，并且你不能一次加载所有的元素到内存中，你该怎么办？</li>\n</ul>\n",
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