leetcode-problemset/leetcode-cn/originData/count-of-matches-in-tournament.json

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            "title": "Count of Matches in Tournament",
            "titleSlug": "count-of-matches-in-tournament",
            "content": "<p>You are given an integer <code>n</code>, the number of teams in a tournament that has strange rules:</p>\n\n<ul>\n\t<li>If the current number of teams is <strong>even</strong>, each team gets paired with another team. A total of <code>n / 2</code> matches are played, and <code>n / 2</code> teams advance to the next round.</li>\n\t<li>If the current number of teams is <strong>odd</strong>, one team randomly advances in the tournament, and the rest gets paired. A total of <code>(n - 1) / 2</code> matches are played, and <code>(n - 1) / 2 + 1</code> teams advance to the next round.</li>\n</ul>\n\n<p>Return <em>the number of matches played in the tournament until a winner is decided.</em></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 7\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> Details of the tournament: \n- 1st Round: Teams = 7, Matches = 3, and 4 teams advance.\n- 2nd Round: Teams = 4, Matches = 2, and 2 teams advance.\n- 3rd Round: Teams = 2, Matches = 1, and 1 team is declared the winner.\nTotal number of matches = 3 + 2 + 1 = 6.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 14\n<strong>Output:</strong> 13\n<strong>Explanation:</strong> Details of the tournament:\n- 1st Round: Teams = 14, Matches = 7, and 7 teams advance.\n- 2nd Round: Teams = 7, Matches = 3, and 4 teams advance.\n- 3rd Round: Teams = 4, Matches = 2, and 2 teams advance.\n- 4th Round: Teams = 2, Matches = 1, and 1 team is declared the winner.\nTotal number of matches = 7 + 3 + 2 + 1 = 13.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 200</code></li>\n</ul>\n",
            "translatedTitle": "比赛中的配对次数",
            "translatedContent": "<p>给你一个整数 <code>n</code> ，表示比赛中的队伍数。比赛遵循一种独特的赛制：</p>\n\n<ul>\n\t<li>如果当前队伍数是 <strong>偶数</strong> ，那么每支队伍都会与另一支队伍配对。总共进行 <code>n / 2</code> 场比赛，且产生 <code>n / 2</code> 支队伍进入下一轮。</li>\n\t<li>如果当前队伍数为 <strong>奇数</strong> ，那么将会随机轮空并晋级一支队伍，其余的队伍配对。总共进行 <code>(n - 1) / 2</code> 场比赛，且产生 <code>(n - 1) / 2 + 1</code> 支队伍进入下一轮。</li>\n</ul>\n\n<p>返回在比赛中进行的配对次数，直到决出获胜队伍为止。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>n = 7\n<strong>输出：</strong>6\n<strong>解释：</strong>比赛详情：\n- 第 1 轮：队伍数 = 7 ，配对次数 = 3 ，4 支队伍晋级。\n- 第 2 轮：队伍数 = 4 ，配对次数 = 2 ，2 支队伍晋级。\n- 第 3 轮：队伍数 = 2 ，配对次数 = 1 ，决出 1 支获胜队伍。\n总配对次数 = 3 + 2 + 1 = 6\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>n = 14\n<strong>输出：</strong>13\n<strong>解释：</strong>比赛详情：\n- 第 1 轮：队伍数 = 14 ，配对次数 = 7 ，7 支队伍晋级。\n- 第 2 轮：队伍数 = 7 ，配对次数 = 3 ，4 支队伍晋级。 \n- 第 3 轮：队伍数 = 4 ，配对次数 = 2 ，2 支队伍晋级。\n- 第 4 轮：队伍数 = 2 ，配对次数 = 1 ，决出 1 支获胜队伍。\n总配对次数 = 7 + 3 + 2 + 1 = 13\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 200</code></li>\n</ul>\n",
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