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61 lines
2.2 KiB
HTML
61 lines
2.2 KiB
HTML
<p>Table: <code>Insurance</code></p>
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<pre>
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+-------------+-------+
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| Column Name | Type |
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+-------------+-------+
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| pid | int |
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| tiv_2015 | float |
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| tiv_2016 | float |
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| lat | float |
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| lon | float |
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+-------------+-------+
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pid is the primary key (column with unique values) for this table.
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Each row of this table contains information about one policy where:
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pid is the policyholder's policy ID.
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tiv_2015 is the total investment value in 2015 and tiv_2016 is the total investment value in 2016.
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lat is the latitude of the policy holder's city. It's guaranteed that lat is not NULL.
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lon is the longitude of the policy holder's city. It's guaranteed that lon is not NULL.
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</pre>
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<p> </p>
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<p>Write a solution to report the sum of all total investment values in 2016 <code>tiv_2016</code>, for all policyholders who:</p>
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<ul>
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<li>have the same <code>tiv_2015</code> value as one or more other policyholders, and</li>
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<li>are not located in the same city as any other policyholder (i.e., the (<code>lat, lon</code>) attribute pairs must be unique).</li>
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</ul>
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<p>Round <code>tiv_2016</code> to <strong>two decimal places</strong>.</p>
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<p>The result format is in the following example.</p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong>
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Insurance table:
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+-----+----------+----------+-----+-----+
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| pid | tiv_2015 | tiv_2016 | lat | lon |
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+-----+----------+----------+-----+-----+
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| 1 | 10 | 5 | 10 | 10 |
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| 2 | 20 | 20 | 20 | 20 |
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| 3 | 10 | 30 | 20 | 20 |
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| 4 | 10 | 40 | 40 | 40 |
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+-----+----------+----------+-----+-----+
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<strong>Output:</strong>
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+----------+
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| tiv_2016 |
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+----------+
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| 45.00 |
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+----------+
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<strong>Explanation:</strong>
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The first record in the table, like the last record, meets both of the two criteria.
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The tiv_2015 value 10 is the same as the third and fourth records, and its location is unique.
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The second record does not meet any of the two criteria. Its tiv_2015 is not like any other policyholders and its location is the same as the third record, which makes the third record fail, too.
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So, the result is the sum of tiv_2016 of the first and last record, which is 45.
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</pre>
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