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leetcode-problemset/leetcode-cn/originData/zui-xiao-de-kge-shu-lcof.json
2023-12-09 19:57:46 +08:00

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{
"data": {
"question": {
"questionId": "100301",
"questionFrontendId": "LCR 159",
"categoryTitle": "Algorithms",
"boundTopicId": 87062,
"title": "库存管理 III",
"titleSlug": "zui-xiao-de-kge-shu-lcof",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "库存管理 III",
"translatedContent": "<p>仓库管理员以数组 <code>stock</code> 形式记录商品库存表,其中 <code>stock[i]</code> 表示对应商品库存余量。请返回库存余量最少的 <code>cnt</code> 个商品余量,返回&nbsp;<strong>顺序不限</strong>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>stock = [2,5,7,4], cnt = 1\n<strong>输出:</strong>[2]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>stock = [0,2,3,6], cnt = 2\n<strong>输出:</strong>[0,2] 或 [2,0]</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= cnt &lt;= stock.length &lt;= 10000<br />\n\t0 &lt;= stock[i] &lt;= 10000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n",
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"difficulty": "Easy",
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"code": "class Solution {\npublic:\n vector<int> inventoryManagement(vector<int>& stock, int cnt) {\n\n }\n};",
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"code": "class Solution(object):\n def inventoryManagement(self, stock, cnt):\n \"\"\"\n :type stock: List[int]\n :type cnt: int\n :rtype: List[int]\n \"\"\"",
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"code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* inventoryManagement(int* stock, int stockSize, int cnt, int* returnSize) {\n \n}",
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