leetcode-problemset/leetcode-cn/originData/validate-stack-sequences.json

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            "questionId": "983",
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            "categoryTitle": "Algorithms",
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            "title": "Validate Stack Sequences",
            "titleSlug": "validate-stack-sequences",
            "content": "<p>Given two integer arrays <code>pushed</code> and <code>popped</code> each with distinct values, return <code>true</code><em> if this could have been the result of a sequence of push and pop operations on an initially empty stack, or </em><code>false</code><em> otherwise.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> pushed = [1,2,3,4,5], popped = [4,5,3,2,1]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> We might do the following sequence:\npush(1), push(2), push(3), push(4),\npop() -&gt; 4,\npush(5),\npop() -&gt; 5, pop() -&gt; 3, pop() -&gt; 2, pop() -&gt; 1\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> pushed = [1,2,3,4,5], popped = [4,3,5,1,2]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> 1 cannot be popped before 2.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= pushed.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= pushed[i] &lt;= 1000</code></li>\n\t<li>All the elements of <code>pushed</code> are <strong>unique</strong>.</li>\n\t<li><code>popped.length == pushed.length</code></li>\n\t<li><code>popped</code> is a permutation of <code>pushed</code>.</li>\n</ul>\n",
            "translatedTitle": "验证栈序列",
            "translatedContent": "<p>给定&nbsp;<code>pushed</code>&nbsp;和&nbsp;<code>popped</code>&nbsp;两个序列，每个序列中的 <strong>值都不重复</strong>，只有当它们可能是在最初空栈上进行的推入 push 和弹出 pop 操作序列的结果时，返回 <code>true</code>；否则，返回 <code>false</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>pushed = [1,2,3,4,5], popped = [4,5,3,2,1]\n<strong>输出：</strong>true\n<strong>解释：</strong>我们可以按以下顺序执行：\npush(1), push(2), push(3), push(4), pop() -&gt; 4,\npush(5), pop() -&gt; 5, pop() -&gt; 3, pop() -&gt; 2, pop() -&gt; 1\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>pushed = [1,2,3,4,5], popped = [4,3,5,1,2]\n<strong>输出：</strong>false\n<strong>解释：</strong>1 不能在 2 之前弹出。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= pushed.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= pushed[i] &lt;= 1000</code></li>\n\t<li><code>pushed</code> 的所有元素 <strong>互不相同</strong></li>\n\t<li><code>popped.length == pushed.length</code></li>\n\t<li><code>popped</code> 是 <code>pushed</code> 的一个排列</li>\n</ul>\n",
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