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leetcode-problemset/leetcode-cn/originData/take-gifts-from-the-richest-pile.json
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{
"data": {
"question": {
"questionId": "2692",
"questionFrontendId": "2558",
"categoryTitle": "Algorithms",
"boundTopicId": 2089975,
"title": "Take Gifts From the Richest Pile",
"titleSlug": "take-gifts-from-the-richest-pile",
"content": "<p>You are given an integer array <code>gifts</code> denoting the number of gifts in various piles. Every second, you do the following:</p>\n\n<ul>\n\t<li>Choose the pile with the maximum number of gifts.</li>\n\t<li>If there is more than one pile with the maximum number of gifts, choose any.</li>\n\t<li>Leave behind the floor of the square root of the number of gifts in the pile. Take the rest of the gifts.</li>\n</ul>\n\n<p>Return <em>the number of gifts remaining after </em><code>k</code><em> seconds.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> gifts = [25,64,9,4,100], k = 4\n<strong>Output:</strong> 29\n<strong>Explanation:</strong> \nThe gifts are taken in the following way:\n- In the first second, the last pile is chosen and 10 gifts are left behind.\n- Then the second pile is chosen and 8 gifts are left behind.\n- After that the first pile is chosen and 5 gifts are left behind.\n- Finally, the last pile is chosen again and 3 gifts are left behind.\nThe final remaining gifts are [5,8,9,4,3], so the total number of gifts remaining is 29.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> gifts = [1,1,1,1], k = 4\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> \nIn this case, regardless which pile you choose, you have to leave behind 1 gift in each pile. \nThat is, you can&#39;t take any pile with you. \nSo, the total gifts remaining are 4.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= gifts.length &lt;= 10<sup>3</sup></code></li>\n\t<li><code>1 &lt;= gifts[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>3</sup></code></li>\n</ul>\n",
"translatedTitle": "从数量最多的堆取走礼物",
"translatedContent": "<p>给你一个整数数组 <code>gifts</code> ,表示各堆礼物的数量。每一秒,你需要执行以下操作:</p>\n\n<ul>\n\t<li>选择礼物数量最多的那一堆。</li>\n\t<li>如果不止一堆都符合礼物数量最多,从中选择任一堆即可。</li>\n\t<li>选中的那一堆留下平方根数量的礼物(向下取整),取走其他的礼物。</li>\n</ul>\n\n<p>返回在 <code>k</code> 秒后剩下的礼物数量<em>。</em></p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>gifts = [25,64,9,4,100], k = 4\n<strong>输出:</strong>29\n<strong>解释:</strong> \n按下述方式取走礼物\n- 在第一秒,选中最后一堆,剩下 10 个礼物。\n- 接着第二秒选中第二堆礼物,剩下 8 个礼物。\n- 然后选中第一堆礼物,剩下 5 个礼物。\n- 最后,再次选中最后一堆礼物,剩下 3 个礼物。\n最后剩下的礼物数量分别是 [5,8,9,4,3] ,所以,剩下礼物的总数量是 29 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>gifts = [1,1,1,1], k = 4\n<strong>输出:</strong>4\n<strong>解释:</strong>\n在本例中不管选中哪一堆礼物都必须剩下 1 个礼物。 \n也就是说你无法获取任一堆中的礼物。 \n所以剩下礼物的总数量是 4 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= gifts.length &lt;= 10<sup>3</sup></code></li>\n\t<li><code>1 &lt;= gifts[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>3</sup></code></li>\n</ul>\n",
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"hints": [
"How can you keep track of the largest gifts in the array",
"What is an efficient way to find the square root of a number?",
"Can you keep adding up the values of the gifts while ensuring they are in a certain order?",
"Can we use a priority queue or heap here?"
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