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"questionId": "921",
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"categoryTitle": "Algorithms",
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"title": "Spiral Matrix III",
"titleSlug": "spiral-matrix-iii",
"content": "<p>You start at the cell <code>(rStart, cStart)</code> of an <code>rows x cols</code> grid facing east. The northwest corner is at the first row and column in the grid, and the southeast corner is at the last row and column.</p>\n\n<p>You will walk in a clockwise spiral shape to visit every position in this grid. Whenever you move outside the grid&#39;s boundary, we continue our walk outside the grid (but may return to the grid boundary later.). Eventually, we reach all <code>rows * cols</code> spaces of the grid.</p>\n\n<p>Return <em>an array of coordinates representing the positions of the grid in the order you visited them</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/08/24/example_1.png\" style=\"width: 174px; height: 99px;\" />\n<pre>\n<strong>Input:</strong> rows = 1, cols = 4, rStart = 0, cStart = 0\n<strong>Output:</strong> [[0,0],[0,1],[0,2],[0,3]]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/08/24/example_2.png\" style=\"width: 202px; height: 142px;\" />\n<pre>\n<strong>Input:</strong> rows = 5, cols = 6, rStart = 1, cStart = 4\n<strong>Output:</strong> [[1,4],[1,5],[2,5],[2,4],[2,3],[1,3],[0,3],[0,4],[0,5],[3,5],[3,4],[3,3],[3,2],[2,2],[1,2],[0,2],[4,5],[4,4],[4,3],[4,2],[4,1],[3,1],[2,1],[1,1],[0,1],[4,0],[3,0],[2,0],[1,0],[0,0]]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= rows, cols &lt;= 100</code></li>\n\t<li><code>0 &lt;= rStart &lt; rows</code></li>\n\t<li><code>0 &lt;= cStart &lt; cols</code></li>\n</ul>\n",
"translatedTitle": "螺旋矩阵 III",
"translatedContent": "<p>在 <code>rows x cols</code> 的网格上,你从单元格 <code>(rStart, cStart)</code> 面朝东面开始。网格的西北角位于第一行第一列,网格的东南角位于最后一行最后一列。</p>\n\n<p>你需要以顺时针按螺旋状行走,访问此网格中的每个位置。每当移动到网格的边界之外时,需要继续在网格之外行走(但稍后可能会返回到网格边界)。</p>\n\n<p>最终,我们到过网格的所有&nbsp;<code>rows x cols</code>&nbsp;个空间。</p>\n\n<p>按照访问顺序返回表示网格位置的坐标列表。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/08/24/example_1.png\" style=\"width: 174px; height: 99px;\" />\n<pre>\n<strong>输入:</strong>rows = 1, cols = 4, rStart = 0, cStart = 0\n<strong>输出:</strong>[[0,0],[0,1],[0,2],[0,3]]\n</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/08/24/example_2.png\" style=\"width: 202px; height: 142px;\" />\n<pre>\n<strong>输入:</strong>rows = 5, cols = 6, rStart = 1, cStart = 4\n<strong>输出:</strong>[[1,4],[1,5],[2,5],[2,4],[2,3],[1,3],[0,3],[0,4],[0,5],[3,5],[3,4],[3,3],[3,2],[2,2],[1,2],[0,2],[4,5],[4,4],[4,3],[4,2],[4,1],[3,1],[2,1],[1,1],[0,1],[4,0],[3,0],[2,0],[1,0],[0,0]]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= rows, cols &lt;= 100</code></li>\n\t<li><code>0 &lt;= rStart &lt; rows</code></li>\n\t<li><code>0 &lt;= cStart &lt; cols</code></li>\n</ul>\n",
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"code": "class Solution(object):\n def spiralMatrixIII(self, rows, cols, rStart, cStart):\n \"\"\"\n :type rows: int\n :type cols: int\n :type rStart: int\n :type cStart: int\n :rtype: List[List[int]]\n \"\"\"",
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