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"question": {
"questionId": "671",
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"categoryTitle": "Algorithms",
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"title": "Second Minimum Node In a Binary Tree",
"titleSlug": "second-minimum-node-in-a-binary-tree",
"content": "<p>Given a non-empty special binary tree consisting of nodes with the non-negative value, where each node in this tree has exactly <code>two</code> or <code>zero</code> sub-node. If the node has two sub-nodes, then this node&#39;s value is the smaller value among its two sub-nodes. More formally, the property&nbsp;<code>root.val = min(root.left.val, root.right.val)</code>&nbsp;always holds.</p>\n\n<p>Given such a binary tree, you need to output the <b>second minimum</b> value in the set made of all the nodes&#39; value in the whole tree.</p>\n\n<p>If no such second minimum value exists, output -1 instead.</p>\n\n<p>&nbsp;</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/15/smbt1.jpg\" style=\"width: 431px; height: 302px;\" />\n<pre>\n<strong>Input:</strong> root = [2,2,5,null,null,5,7]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> The smallest value is 2, the second smallest value is 5.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/15/smbt2.jpg\" style=\"width: 321px; height: 182px;\" />\n<pre>\n<strong>Input:</strong> root = [2,2,2]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> The smallest value is 2, but there isn&#39;t any second smallest value.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 25]</code>.</li>\n\t<li><code>1 &lt;= Node.val &lt;= 2<sup>31</sup> - 1</code></li>\n\t<li><code>root.val == min(root.left.val, root.right.val)</code>&nbsp;for each internal node of the tree.</li>\n</ul>\n",
"translatedTitle": "二叉树中第二小的节点",
"translatedContent": "<p>给定一个非空特殊的二叉树,每个节点都是正数,并且每个节点的子节点数量只能为&nbsp;<code>2</code>&nbsp;或&nbsp;<code>0</code>。如果一个节点有两个子节点的话,那么该节点的值等于两个子节点中较小的一个。</p>\n\n<p>更正式地说,即&nbsp;<code>root.val = min(root.left.val, root.right.val)</code> 总成立。</p>\n\n<p>给出这样的一个二叉树,你需要输出所有节点中的&nbsp;<strong>第二小的值 </strong>。</p>\n\n<p>如果第二小的值不存在的话,输出 -1 <strong>。</strong></p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/15/smbt1.jpg\" style=\"height: 210px; width: 300px;\" />\n<pre>\n<strong>输入:</strong>root = [2,2,5,null,null,5,7]\n<strong>输出:</strong>5\n<strong>解释:</strong>最小的值是 2 ,第二小的值是 5 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/15/smbt2.jpg\" style=\"height: 113px; width: 200px;\" />\n<pre>\n<strong>输入:</strong>root = [2,2,2]\n<strong>输出:</strong>-1\n<strong>解释:</strong>最小的值是 2, 但是不存在第二小的值。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>树中节点数目在范围 <code>[1, 25]</code> 内</li>\n\t<li><code>1 &lt;= Node.val &lt;= 2<sup>31</sup> - 1</code></li>\n\t<li>对于树中每个节点 <code>root.val == min(root.left.val, root.right.val)</code></li>\n</ul>\n",
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