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{
"data": {
"question": {
"questionId": "2196",
"questionFrontendId": "2074",
"categoryTitle": "Algorithms",
"boundTopicId": 1097207,
"title": "Reverse Nodes in Even Length Groups",
"titleSlug": "reverse-nodes-in-even-length-groups",
"content": "<p>You are given the <code>head</code> of a linked list.</p>\n\n<p>The nodes in the linked list are <strong>sequentially</strong> assigned to <strong>non-empty</strong> groups whose lengths form the sequence of the natural numbers (<code>1, 2, 3, 4, ...</code>). The <strong>length</strong> of a group is the number of nodes assigned to it. In other words,</p>\n\n<ul>\n\t<li>The <code>1<sup>st</sup></code> node is assigned to the first group.</li>\n\t<li>The <code>2<sup>nd</sup></code> and the <code>3<sup>rd</sup></code> nodes are assigned to the second group.</li>\n\t<li>The <code>4<sup>th</sup></code>, <code>5<sup>th</sup></code>, and <code>6<sup>th</sup></code> nodes are assigned to the third group, and so on.</li>\n</ul>\n\n<p>Note that the length of the last group may be less than or equal to <code>1 + the length of the second to last group</code>.</p>\n\n<p><strong>Reverse</strong> the nodes in each group with an <strong>even</strong> length, and return <em>the</em> <code>head</code> <em>of the modified linked list</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/25/eg1.png\" style=\"width: 699px; height: 124px;\" />\n<pre>\n<strong>Input:</strong> head = [5,2,6,3,9,1,7,3,8,4]\n<strong>Output:</strong> [5,6,2,3,9,1,4,8,3,7]\n<strong>Explanation:</strong>\n- The length of the first group is 1, which is odd, hence no reversal occurs.\n- The length of the second group is 2, which is even, hence the nodes are reversed.\n- The length of the third group is 3, which is odd, hence no reversal occurs.\n- The length of the last group is 4, which is even, hence the nodes are reversed.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/25/eg2.png\" style=\"width: 284px; height: 114px;\" />\n<pre>\n<strong>Input:</strong> head = [1,1,0,6]\n<strong>Output:</strong> [1,0,1,6]\n<strong>Explanation:</strong>\n- The length of the first group is 1. No reversal occurs.\n- The length of the second group is 2. The nodes are reversed.\n- The length of the last group is 1. No reversal occurs.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/11/17/ex3.png\" style=\"width: 348px; height: 114px;\" />\n<pre>\n<strong>Input:</strong> head = [1,1,0,6,5]\n<strong>Output:</strong> [1,0,1,5,6]\n<strong>Explanation:</strong>\n- The length of the first group is 1. No reversal occurs.\n- The length of the second group is 2. The nodes are reversed.\n- The length of the last group is 2. The nodes are reversed.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the list is in the range <code>[1, 10<sup>5</sup>]</code>.</li>\n\t<li><code>0 &lt;= Node.val &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
"translatedTitle": "反转偶数长度组的节点",
"translatedContent": "<p>给你一个链表的头节点 <code>head</code> 。</p>\n\n<p>链表中的节点 <strong>按顺序</strong> 划分成若干 <strong>非空</strong> 组,这些非空组的长度构成一个自然数序列(<code>1, 2, 3, 4, ...</code>)。一个组的 <strong>长度</strong> 就是组中分配到的节点数目。换句话说:</p>\n\n<ul>\n\t<li>节点 <code>1</code> 分配给第一组</li>\n\t<li>节点 <code>2</code> 和 <code>3</code> 分配给第二组</li>\n\t<li>节点 <code>4</code>、<code>5</code> 和 <code>6</code> 分配给第三组,以此类推</li>\n</ul>\n\n<p>注意,最后一组的长度可能小于或者等于 <code>1 + 倒数第二组的长度</code> 。</p>\n\n<p><strong>反转</strong> 每个 <strong>偶数</strong> 长度组中的节点,并返回修改后链表的头节点 <code>head</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/25/eg1.png\" style=\"width: 699px; height: 124px;\" /></p>\n\n<pre>\n<strong>输入:</strong>head = [5,2,6,3,9,1,7,3,8,4]\n<strong>输出:</strong>[5,6,2,3,9,1,4,8,3,7]\n<strong>解释:</strong>\n- 第一组长度为 1 ,奇数,没有发生反转。\n- 第二组长度为 2 ,偶数,节点反转。\n- 第三组长度为 3 ,奇数,没有发生反转。\n- 最后一组长度为 4 ,偶数,节点反转。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/25/eg2.png\" style=\"width: 284px; height: 114px;\" /></p>\n\n<pre>\n<strong>输入:</strong>head = [1,1,0,6]\n<strong>输出:</strong>[1,0,1,6]\n<strong>解释:</strong>\n- 第一组长度为 1 ,没有发生反转。\n- 第二组长度为 2 ,节点反转。\n- 最后一组长度为 1 ,没有发生反转。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/28/eg3.png\" style=\"width: 139px; height: 114px;\" /></p>\n\n<pre>\n<strong>输入:</strong>head = [2,1]\n<strong>输出:</strong>[2,1]\n<strong>解释:</strong>\n- 第一组长度为 1 ,没有发生反转。\n- 最后一组长度为 1 ,没有发生反转。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>链表中节点数目范围是 <code>[1, 10<sup>5</sup>]</code></li>\n\t<li><code>0 &lt;= Node.val &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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"Consider the list structure ...A → (B → ... → C) → D..., where the nodes between B and C (inclusive) form a group, A is the last node of the previous group, and D is the first node of the next group. How can you utilize this structure?",
"Suppose you have B → ... → C reversed (because it was of even length) so that it is now C → ... → B. What references do you need to fix so that the transitions between the previous, current, and next groups are correct?",
"A.next should be set to C, and B.next should be set to D.",
"Once the current group is finished being modified, you need to find the new A, B, C, and D nodes for the next group. How can you use the old A, B, C, and D nodes to find the new ones?",
"The new A is either the old B or old C depending on if the group was of even or odd length. The new B is always the old D. The new C and D can be found based on the new B and the next group's length.",
"You can set the initial values of A, B, C, and D to A = null, B = head, C = head, D = head.next. Repeat the steps from the previous hints until D is null."
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