leetcode-problemset/leetcode-cn/originData/permutation-in-string.json

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            "categoryTitle": "Algorithms",
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            "title": "Permutation in String",
            "titleSlug": "permutation-in-string",
            "content": "<p>Given two strings <code>s1</code> and <code>s2</code>, return <code>true</code><em> if </em><code>s2</code><em> contains a permutation of </em><code>s1</code><em>, or </em><code>false</code><em> otherwise</em>.</p>\n\n<p>In other words, return <code>true</code> if one of <code>s1</code>&#39;s permutations is the substring of <code>s2</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;ab&quot;, s2 = &quot;eidbaooo&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> s2 contains one permutation of s1 (&quot;ba&quot;).\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;ab&quot;, s2 = &quot;eidboaoo&quot;\n<strong>Output:</strong> false\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s1.length, s2.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>s1</code> and <code>s2</code> consist of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "字符串的排列",
            "translatedContent": "<p>给你两个字符串&nbsp;<code>s1</code>&nbsp;和&nbsp;<code>s2</code> ，写一个函数来判断 <code>s2</code> 是否包含 <code>s1</code><strong>&nbsp;</strong>的排列。如果是，返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p>换句话说，<code>s1</code> 的排列之一是 <code>s2</code> 的 <strong>子串</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1 = \"ab\" s2 = \"eidbaooo\"\n<strong>输出：</strong>true\n<strong>解释：</strong>s2 包含 s1 的排列之一 (\"ba\").\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1= \"ab\" s2 = \"eidboaoo\"\n<strong>输出：</strong>false\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s1.length, s2.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>s1</code> 和 <code>s2</code> 仅包含小写字母</li>\n</ul>\n",
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            "hints": [
                "Obviously, brute force will result in TLE. Think of something else.",
                "How will you check whether one string is a permutation of another string?",
                "One way is to sort the string and then compare. But, Is there a better way?",
                "If one string is a permutation of another string then they must one common metric. What is that?",
                "Both strings must have same character frequencies, if  one is permutation of another. Which data structure should be used to store frequencies?",
                "What about hash table?  An array of size 26?"
            ],
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