leetcode-problemset/leetcode-cn/originData/permutation-i-lcci.json

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            "questionId": "100241",
            "questionFrontendId": "面试题 08.07",
            "categoryTitle": "LCCI",
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            "title": "Permutation I LCCI",
            "titleSlug": "permutation-i-lcci",
            "content": "<p>Write a method to compute all permutations of a string of unique characters.</p>\r\n\r\n<p><strong>Example1:</strong></p>\r\n\r\n<pre>\r\n<strong> Input</strong>: S = &quot;qwe&quot;\r\n<strong> Output</strong>: [&quot;qwe&quot;, &quot;qew&quot;, &quot;wqe&quot;, &quot;weq&quot;, &quot;ewq&quot;, &quot;eqw&quot;]\r\n</pre>\r\n\r\n<p><strong>Example2:</strong></p>\r\n\r\n<pre>\r\n<strong> Input</strong>: S = &quot;ab&quot;\r\n<strong> Output</strong>: [&quot;ab&quot;, &quot;ba&quot;]\r\n</pre>\r\n\r\n<p><strong>Note:</strong></p>\r\n\r\n<ol>\r\n\t<li>All charaters are English letters.</li>\r\n\t<li><code>1 &lt;= S.length &lt;= 9</code></li>\r\n</ol>\r\n",
            "translatedTitle": "无重复字符串的排列组合",
            "translatedContent": "<p>无重复字符串的排列组合。编写一种方法，计算某字符串的所有排列组合，字符串每个字符均不相同。</p>\n\n<p> <strong>示例1:</strong></p>\n\n<pre>\n<strong> 输入</strong>：S = \"qwe\"\n<strong> 输出</strong>：[\"qwe\", \"qew\", \"wqe\", \"weq\", \"ewq\", \"eqw\"]\n</pre>\n\n<p> <strong>示例2:</strong></p>\n\n<pre>\n<strong> 输入</strong>：S = \"ab\"\n<strong> 输出</strong>：[\"ab\", \"ba\"]\n</pre>\n\n<p> <strong>提示:</strong></p>\n\n<ol>\n<li>字符都是英文字母。</li>\n<li>字符串长度在[1, 9]之间。</li>\n</ol>\n",
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                    "name": "String",
                    "slug": "string",
                    "translatedName": "字符串",
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                {
                    "lang": "C++",
                    "langSlug": "cpp",
                    "code": "class Solution {\npublic:\n    vector<string> permutation(string S) {\n\n    }\n};",
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                    "code": "class Solution {\n    public String[] permutation(String S) {\n\n    }\n}",
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                {
                    "lang": "Python",
                    "langSlug": "python",
                    "code": "class Solution(object):\n    def permutation(self, S):\n        \"\"\"\n        :type S: str\n        :rtype: List[str]\n        \"\"\"",
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                    "code": "class Solution:\n    def permutation(self, S: str) -> List[str]:",
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                    "code": "\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar** permutation(char* S, int* returnSize){\n\n}\n",
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                    "code": "public class Solution {\n    public string[] Permutation(string S) {\n\n    }\n}",
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                    "code": "/**\n * @param {string} S\n * @return {string[]}\n */\nvar permutation = function(S) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param String $S\n     * @return String[]\n     */\n    function permutation($S) {\n\n    }\n}",
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                    "code": "class Solution {\n    func permutation(_ S: String) -> [String] {\n\n    }\n}",
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                    "lang": "Go",
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                    "code": "func permutation(S string) []string {\n\n}",
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                    "code": "# @param {String} s\n# @return {String[]}\ndef permutation(s)\n\nend",
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                    "lang": "Racket",
                    "langSlug": "racket",
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                    "code": "defmodule Solution do\n  @spec permutation(s :: String.t) :: [String.t]\n  def permutation(s) do\n\n  end\nend",
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            "hints": [
                "方法1：假设你有abc的所有排列。你怎么用它来得到abcd的所有排列？",
                "方法1：abc的排列组合表示abc的所有组合方式。现在，我们要创建abcd的所有组合方式。选择abcd的特定组合，如bdca。这个bdca字符串也代表abc的一种排列方式：删除d，你会得到bca。那么给定字符串bca，你是否可以创建包含d 的所有“相关”排列组合？",
                "方法1：给定一个字符串，比如bca，可以通过将d 插入到每个可能的位置：dbca、bdca、bcda、bcad，来创建abcd（其中abc顺序一定）的所有排列组合。给定abc的所有排列，你可以创建所有abcd的排列吗？",
                "方法1：你可以通过计算abc的所有排列，然后在每个可能的位置插入d，从而创建abcd的所有排列。",
                "方法2：如果你拥有两个字符所有排列的子串，可以生成三个字符全排列的子串吗？",
                "方法2：生成一个abcd的全排列，需要选择一个初始字符。它可以是a、b、c或d。然后你可以排列其余的字符。如何使用这种方法生成完整字符串的所有排列？",
                "方法 2：要生成abcd的所有排列组合，请选择每个字符（a、b、c、d）作为首字符。排列剩余的字符并追加首字符。如何排列剩余的字符？使用遵循相同逻辑的递归过程。",
                "方法 2：你可以通过让递归函数返回字符串列表来实现该方法，然后在它上面追加首字符。或者，你可以将前缀下推到递归调用中。"
            ],
            "solution": null,
            "status": null,
            "sampleTestCase": "\"qwe\"",
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