mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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180 lines
27 KiB
JSON
180 lines
27 KiB
JSON
{
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"questionId": "437",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1255,
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"title": "Path Sum III",
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"titleSlug": "path-sum-iii",
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"content": "<p>Given the <code>root</code> of a binary tree and an integer <code>targetSum</code>, return <em>the number of paths where the sum of the values along the path equals</em> <code>targetSum</code>.</p>\n\n<p>The path does not need to start or end at the root or a leaf, but it must go downwards (i.e., traveling only from parent nodes to child nodes).</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/09/pathsum3-1-tree.jpg\" style=\"width: 450px; height: 386px;\" />\n<pre>\n<strong>Input:</strong> root = [10,5,-3,3,2,null,11,3,-2,null,1], targetSum = 8\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The paths that sum to 8 are shown.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22\n<strong>Output:</strong> 3\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[0, 1000]</code>.</li>\n\t<li><code>-10<sup>9</sup> <= Node.val <= 10<sup>9</sup></code></li>\n\t<li><code>-1000 <= targetSum <= 1000</code></li>\n</ul>\n",
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"translatedTitle": "路径总和 III",
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"translatedContent": "<p>给定一个二叉树的根节点 <code>root</code> ，和一个整数 <code>targetSum</code> ，求该二叉树里节点值之和等于 <code>targetSum</code> 的 <strong>路径</strong> 的数目。</p>\n\n<p><strong>路径</strong> 不需要从根节点开始，也不需要在叶子节点结束，但是路径方向必须是向下的（只能从父节点到子节点）。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/04/09/pathsum3-1-tree.jpg\" style=\"width: 452px; \" /></p>\n\n<pre>\n<strong>输入：</strong>root = [10,5,-3,3,2,null,11,3,-2,null,1], targetSum = 8\n<strong>输出：</strong>3\n<strong>解释：</strong>和等于 8 的路径有 3 条，如图所示。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22\n<strong>输出：</strong>3\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>二叉树的节点个数的范围是 <code>[0,1000]</code></li>\n\t<li><meta charset=\"UTF-8\" /><code>-10<sup>9</sup> <= Node.val <= 10<sup>9</sup></code> </li>\n\t<li><code>-1000 <= targetSum <= 1000</code> </li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $targetSum\n * @return Integer\n */\n function pathSum($root, $targetSum) {\n\n }\n}",
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