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{
"data": {
"question": {
"questionId": "1000300",
"questionFrontendId": "LCR 108",
"categoryTitle": "Algorithms",
"boundTopicId": 910294,
"title": "单词接龙",
"titleSlug": "om3reC",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "单词接龙",
"translatedContent": "<p>在字典(单词列表)&nbsp;<code>wordList</code> 中,从单词 <code>beginWord</code><em>&nbsp;</em>和 <code>endWord</code> 的 <strong>转换序列 </strong>是一个按下述规格形成的序列:</p>\n\n<ul>\n\t<li>序列中第一个单词是 <code>beginWord</code> 。</li>\n\t<li>序列中最后一个单词是 <code>endWord</code> 。</li>\n\t<li>每次转换只能改变一个字母。</li>\n\t<li>转换过程中的中间单词必须是字典&nbsp;<code>wordList</code> 中的单词。</li>\n</ul>\n\n<p>给定两个长度相同但内容不同的单词<em> </em><code>beginWord</code><em>&nbsp;</em>和 <code>endWord</code> 和一个字典 <code>wordList</code> ,找到从&nbsp;<code>beginWord</code> 到&nbsp;<code>endWord</code> 的 <strong>最短转换序列</strong> 中的 <strong>单词数目</strong> 。如果不存在这样的转换序列,返回 0。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>beginWord = &quot;hit&quot;, endWord = &quot;cog&quot;, wordList = [&quot;hot&quot;,&quot;dot&quot;,&quot;dog&quot;,&quot;lot&quot;,&quot;log&quot;,&quot;cog&quot;]\n<strong>输出:</strong>5\n<strong>解释:</strong>一个最短转换序列是 &quot;hit&quot; -&gt; &quot;hot&quot; -&gt; &quot;dot&quot; -&gt; &quot;dog&quot; -&gt; &quot;cog&quot;, 返回它的长度 5。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>beginWord = &quot;hit&quot;, endWord = &quot;cog&quot;, wordList = [&quot;hot&quot;,&quot;dot&quot;,&quot;dog&quot;,&quot;lot&quot;,&quot;log&quot;]\n<strong>输出:</strong>0\n<strong>解释:</strong>endWord &quot;cog&quot; 不在字典中,所以无法进行转换。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= beginWord.length &lt;= 10</code></li>\n\t<li><code>endWord.length == beginWord.length</code></li>\n\t<li><code>1 &lt;= wordList.length &lt;= 5000</code></li>\n\t<li><code>wordList[i].length == beginWord.length</code></li>\n\t<li><code>beginWord</code>、<code>endWord</code> 和 <code>wordList[i]</code> 由小写英文字母组成</li>\n\t<li><code>beginWord != endWord</code></li>\n\t<li><code>wordList</code> 中的所有字符串 <strong>互不相同</strong></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意:本题与主站 127&nbsp;题相同:&nbsp;<a href=\"https://leetcode-cn.com/problems/word-ladder/\">https://leetcode-cn.com/problems/word-ladder/</a></p>\n",
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"lang": "C++",
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"code": "class Solution {\npublic:\n int ladderLength(string beginWord, string endWord, vector<string>& wordList) {\n\n }\n};",
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"code": "class Solution(object):\n def ladderLength(self, beginWord, endWord, wordList):\n \"\"\"\n :type beginWord: str\n :type endWord: str\n :type wordList: List[str]\n :rtype: int\n \"\"\"",
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"code": "\n\nint ladderLength(char * beginWord, char * endWord, char ** wordList, int wordListSize){\n\n}",
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"code": "public class Solution {\n public int LadderLength(string beginWord, string endWord, IList<string> wordList) {\n\n }\n}",
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"code": "class Solution {\n\n /**\n * @param String $beginWord\n * @param String $endWord\n * @param String[] $wordList\n * @return Integer\n */\n function ladderLength($beginWord, $endWord, $wordList) {\n\n }\n}",
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"code": "class Solution {\n func ladderLength(_ beginWord: String, _ endWord: String, _ wordList: [String]) -> Int {\n\n }\n}",
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"code": "class Solution {\n fun ladderLength(beginWord: String, endWord: String, wordList: List<String>): Int {\n\n }\n}",
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"code": "# @param {String} begin_word\n# @param {String} end_word\n# @param {String[]} word_list\n# @return {Integer}\ndef ladder_length(begin_word, end_word, word_list)\n\nend",
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"code": "object Solution {\n def ladderLength(beginWord: String, endWord: String, wordList: List[String]): Int = {\n\n }\n}",
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"lang": "Rust",
"langSlug": "rust",
"code": "impl Solution {\n pub fn ladder_length(begin_word: String, end_word: String, word_list: Vec<String>) -> i32 {\n\n }\n}",
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"code": "(define/contract (ladder-length beginWord endWord wordList)\n (-> string? string? (listof string?) exact-integer?)\n\n )",
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"code": "-spec ladder_length(BeginWord :: unicode:unicode_binary(), EndWord :: unicode:unicode_binary(), WordList :: [unicode:unicode_binary()]) -> integer().\nladder_length(BeginWord, EndWord, WordList) ->\n .",
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"code": "defmodule Solution do\n @spec ladder_length(begin_word :: String.t, end_word :: String.t, word_list :: [String.t]) :: integer\n def ladder_length(begin_word, end_word, word_list) do\n\n end\nend",
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"sampleTestCase": "\"hit\"\n\"cog\"\n[\"hot\",\"dot\",\"dog\",\"lot\",\"log\",\"cog\"]",
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