leetcode-problemset/leetcode-cn/originData/number-of-ways-to-form-a-target-string-given-a-dictionary.json

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        "question": {
            "questionId": "1744",
            "questionFrontendId": "1639",
            "categoryTitle": "Algorithms",
            "boundTopicId": 466360,
            "title": "Number of Ways to Form a Target String Given a Dictionary",
            "titleSlug": "number-of-ways-to-form-a-target-string-given-a-dictionary",
            "content": "<p>You are given a list of strings of the <strong>same length</strong> <code>words</code> and a string <code>target</code>.</p>\n\n<p>Your task is to form <code>target</code> using the given <code>words</code> under the following rules:</p>\n\n<ul>\n\t<li><code>target</code> should be formed from left to right.</li>\n\t<li>To form the <code>i<sup>th</sup></code> character (<strong>0-indexed</strong>) of <code>target</code>, you can choose the <code>k<sup>th</sup></code> character of the <code>j<sup>th</sup></code> string in <code>words</code> if <code>target[i] = words[j][k]</code>.</li>\n\t<li>Once you use the <code>k<sup>th</sup></code> character of the <code>j<sup>th</sup></code> string of <code>words</code>, you <strong>can no longer</strong> use the <code>x<sup>th</sup></code> character of any string in <code>words</code> where <code>x &lt;= k</code>. In other words, all characters to the left of or at index <code>k</code> become unusuable for every string.</li>\n\t<li>Repeat the process until you form the string <code>target</code>.</li>\n</ul>\n\n<p><strong>Notice</strong> that you can use <strong>multiple characters</strong> from the <strong>same string</strong> in <code>words</code> provided the conditions above are met.</p>\n\n<p>Return <em>the number of ways to form <code>target</code> from <code>words</code></em>. Since the answer may be too large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;acca&quot;,&quot;bbbb&quot;,&quot;caca&quot;], target = &quot;aba&quot;\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> There are 6 ways to form target.\n&quot;aba&quot; -&gt; index 0 (&quot;<u>a</u>cca&quot;), index 1 (&quot;b<u>b</u>bb&quot;), index 3 (&quot;cac<u>a</u>&quot;)\n&quot;aba&quot; -&gt; index 0 (&quot;<u>a</u>cca&quot;), index 2 (&quot;bb<u>b</u>b&quot;), index 3 (&quot;cac<u>a</u>&quot;)\n&quot;aba&quot; -&gt; index 0 (&quot;<u>a</u>cca&quot;), index 1 (&quot;b<u>b</u>bb&quot;), index 3 (&quot;acc<u>a</u>&quot;)\n&quot;aba&quot; -&gt; index 0 (&quot;<u>a</u>cca&quot;), index 2 (&quot;bb<u>b</u>b&quot;), index 3 (&quot;acc<u>a</u>&quot;)\n&quot;aba&quot; -&gt; index 1 (&quot;c<u>a</u>ca&quot;), index 2 (&quot;bb<u>b</u>b&quot;), index 3 (&quot;acc<u>a</u>&quot;)\n&quot;aba&quot; -&gt; index 1 (&quot;c<u>a</u>ca&quot;), index 2 (&quot;bb<u>b</u>b&quot;), index 3 (&quot;cac<u>a</u>&quot;)\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;abba&quot;,&quot;baab&quot;], target = &quot;bab&quot;\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> There are 4 ways to form target.\n&quot;bab&quot; -&gt; index 0 (&quot;<u>b</u>aab&quot;), index 1 (&quot;b<u>a</u>ab&quot;), index 2 (&quot;ab<u>b</u>a&quot;)\n&quot;bab&quot; -&gt; index 0 (&quot;<u>b</u>aab&quot;), index 1 (&quot;b<u>a</u>ab&quot;), index 3 (&quot;baa<u>b</u>&quot;)\n&quot;bab&quot; -&gt; index 0 (&quot;<u>b</u>aab&quot;), index 2 (&quot;ba<u>a</u>b&quot;), index 3 (&quot;baa<u>b</u>&quot;)\n&quot;bab&quot; -&gt; index 1 (&quot;a<u>b</u>ba&quot;), index 2 (&quot;ba<u>a</u>b&quot;), index 3 (&quot;baa<u>b</u>&quot;)\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 1000</code></li>\n\t<li>All strings in <code>words</code> have the same length.</li>\n\t<li><code>1 &lt;= target.length &lt;= 1000</code></li>\n\t<li><code>words[i]</code> and <code>target</code> contain only lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "通过给定词典构造目标字符串的方案数",
            "translatedContent": "<p>给你一个字符串列表 <code>words</code> 和一个目标字符串 <code>target</code> 。<code>words</code> 中所有字符串都 <strong>长度相同</strong>  。</p>\n\n<p>你的目标是使用给定的 <code>words</code> 字符串列表按照下述规则构造 <code>target</code> ：</p>\n\n<ul>\n\t<li>从左到右依次构造 <code>target</code> 的每一个字符。</li>\n\t<li>为了得到 <code>target</code> 第 <code>i</code> 个字符（下标从 <strong>0</strong> 开始），当 <code>target[i] = words[j][k]</code> 时，你可以使用 <code>words</code> 列表中第 <code>j</code> 个字符串的第 <code>k</code> 个字符。</li>\n\t<li>一旦你使用了 <code>words</code> 中第 <code>j</code> 个字符串的第 <code>k</code> 个字符，你不能再使用 <code>words</code> 字符串列表中任意单词的第 <code>x</code> 个字符（<code>x <= k</code>）。也就是说，所有单词下标小于等于 <code>k</code> 的字符都不能再被使用。</li>\n\t<li>请你重复此过程直到得到目标字符串 <code>target</code> 。</li>\n</ul>\n\n<p><strong>请注意</strong>， 在构造目标字符串的过程中，你可以按照上述规定使用 <code>words</code> 列表中 <strong>同一个字符串</strong> 的 <strong>多个字符</strong> 。</p>\n\n<p>请你返回使用 <code>words</code> 构造 <code>target</code> 的方案数。由于答案可能会很大，请对 <code>10<sup>9</sup> + 7</code> <strong>取余</strong> 后返回。</p>\n\n<p>（译者注：此题目求的是有多少个不同的 <code>k</code> 序列，详情请见示例。）</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>words = [\"acca\",\"bbbb\",\"caca\"], target = \"aba\"\n<b>输出：</b>6\n<b>解释：</b>总共有 6 种方法构造目标串。\n\"aba\" -> 下标为 0 (\"<strong>a</strong>cca\")，下标为 1 (\"b<strong>b</strong>bb\")，下标为 3 (\"cac<strong>a</strong>\")\n\"aba\" -> 下标为 0 (\"<strong>a</strong>cca\")，下标为 2 (\"bb<strong>b</strong>b\")，下标为 3 (\"cac<strong>a</strong>\")\n\"aba\" -> 下标为 0 (\"<strong>a</strong>cca\")，下标为 1 (\"b<strong>b</strong>bb\")，下标为 3 (\"acc<strong>a</strong>\")\n\"aba\" -> 下标为 0 (\"<strong>a</strong>cca\")，下标为 2 (\"bb<strong>b</strong>b\")，下标为 3 (\"acc<strong>a</strong>\")\n\"aba\" -> 下标为 1 (\"c<strong>a</strong>ca\")，下标为 2 (\"bb<strong>b</strong>b\")，下标为 3 (\"acc<strong>a</strong>\")\n\"aba\" -> 下标为 1 (\"c<strong>a</strong>ca\")，下标为 2 (\"bb<strong>b</strong>b\")，下标为 3 (\"cac<strong>a</strong>\")\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>words = [\"abba\",\"baab\"], target = \"bab\"\n<b>输出：</b>4\n<b>解释：</b>总共有 4 种不同形成 target 的方法。\n\"bab\" -> 下标为 0 (\"<strong>b</strong>aab\")，下标为 1 (\"b<strong>a</strong>ab\")，下标为 2 (\"ab<strong>b</strong>a\")\n\"bab\" -> 下标为 0 (\"<strong>b</strong>aab\")，下标为 1 (\"b<strong>a</strong>ab\")，下标为 3 (\"baa<strong>b</strong>\")\n\"bab\" -> 下标为 0 (\"<strong>b</strong>aab\")，下标为 2 (\"ba<strong>a</strong>b\")，下标为 3 (\"baa<strong>b</strong>\")\n\"bab\" -> 下标为 1 (\"a<strong>b</strong>ba\")，下标为 2 (\"ba<strong>a</strong>b\")，下标为 3 (\"baa<strong>b</strong>\")\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>words = [\"abcd\"], target = \"abcd\"\n<b>输出：</b>1\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<b>输入：</b>words = [\"abab\",\"baba\",\"abba\",\"baab\"], target = \"abba\"\n<b>输出：</b>16\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= words.length <= 1000</code></li>\n\t<li><code>1 <= words[i].length <= 1000</code></li>\n\t<li><code>words</code> 中所有单词长度相同。</li>\n\t<li><code>1 <= target.length <= 1000</code></li>\n\t<li><code>words[i]</code> 和 <code>target</code> 都仅包含小写英文字母。</li>\n</ul>\n",
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