leetcode-problemset/leetcode-cn/originData/minimum-total-cost-to-make-arrays-unequal.json

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            "title": "Minimum Total Cost to Make Arrays Unequal",
            "titleSlug": "minimum-total-cost-to-make-arrays-unequal",
            "content": "<p>You are given two <strong>0-indexed</strong> integer arrays <code>nums1</code> and <code>nums2</code>, of equal length <code>n</code>.</p>\n\n<p>In one operation, you can swap the values of any two indices of <code>nums1</code>. The <strong>cost</strong> of this operation is the <strong>sum</strong> of the indices.</p>\n\n<p>Find the <strong>minimum</strong> total cost of performing the given operation <strong>any</strong> number of times such that <code>nums1[i] != nums2[i]</code> for all <code>0 &lt;= i &lt;= n - 1</code> after performing all the operations.</p>\n\n<p>Return <em>the <strong>minimum total cost</strong> such that </em><code>nums1</code> and <code>nums2</code><em> satisfy the above condition</em>. In case it is not possible, return <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,2,3,4,5], nums2 = [1,2,3,4,5]\n<strong>Output:</strong> 10\n<strong>Explanation:</strong> \nOne of the ways we can perform the operations is:\n- Swap values at indices 0 and 3, incurring cost = 0 + 3 = 3. Now, nums1 = [4,2,3,1,5]\n- Swap values at indices 1 and 2, incurring cost = 1 + 2 = 3. Now, nums1 = [4,3,2,1,5].\n- Swap values at indices 0 and 4, incurring cost = 0 + 4 = 4. Now, nums1 =[5,3,2,1,4].\nWe can see that for each index i, nums1[i] != nums2[i]. The cost required here is 10.\nNote that there are other ways to swap values, but it can be proven that it is not possible to obtain a cost less than 10.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [2,2,2,1,3], nums2 = [1,2,2,3,3]\n<strong>Output:</strong> 10\n<strong>Explanation:</strong> \nOne of the ways we can perform the operations is:\n- Swap values at indices 2 and 3, incurring cost = 2 + 3 = 5. Now, nums1 = [2,2,1,2,3].\n- Swap values at indices 1 and 4, incurring cost = 1 + 4 = 5. Now, nums1 = [2,3,1,2,2].\nThe total cost needed here is 10, which is the minimum possible.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,2,2], nums2 = [1,2,2]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> \nIt can be shown that it is not possible to satisfy the given conditions irrespective of the number of operations we perform.\nHence, we return -1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums1.length == nums2.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[i] &lt;= n</code></li>\n</ul>\n",
            "translatedTitle": "让数组不相等的最小总代价",
            "translatedContent": "<p>给你两个下标从 <strong>0</strong>&nbsp;开始的整数数组&nbsp;<code>nums1</code>&nbsp;和&nbsp;<code>nums2</code>&nbsp;，两者长度都为&nbsp;<code>n</code>&nbsp;。</p>\n\n<p>每次操作中，你可以选择交换 <code>nums1</code>&nbsp;中任意两个下标处的值。操作的 <strong>开销</strong>&nbsp;为两个下标的 <strong>和</strong>&nbsp;。</p>\n\n<p>你的目标是对于所有的 <code>0 &lt;= i &lt;= n - 1</code>&nbsp;，都满足&nbsp;<code>nums1[i] != nums2[i]</code>&nbsp;，你可以进行 <strong>任意次</strong>&nbsp;操作，请你返回达到这个目标的 <strong>最小</strong>&nbsp;总代价。</p>\n\n<p>请你返回让<em>&nbsp;</em><code>nums1</code> 和&nbsp;<code>nums2</code><em>&nbsp;</em>满足上述条件的 <strong>最小总代价</strong> ，如果无法达成目标，返回&nbsp;<code>-1</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums1 = [1,2,3,4,5], nums2 = [1,2,3,4,5]\n<b>输出：</b>10\n<b>解释：</b>\n实现目标的其中一种方法为：\n- 交换下标为 0 和 3 的两个值，代价为 0 + 3 = 3 。现在 nums1 = [4,2,3,1,5] 。\n- 交换下标为 1 和 2 的两个值，代价为 1 + 2 = 3 。现在 nums1 = [4,3,2,1,5] 。\n- 交换下标为 0 和 4 的两个值，代价为 0 + 4 = 4 。现在 nums1 = [5,3,2,1,4] 。\n最后，对于每个下标 i ，都有 nums1[i] != nums2[i] 。总代价为 10 。\n还有别的交换值的方法，但是无法得到代价和小于 10 的方案。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums1 = [2,2,2,1,3], nums2 = [1,2,2,3,3]\n<b>输出：</b>10\n<b>解释：</b>\n实现目标的一种方法为：\n- 交换下标为 2 和 3 的两个值，代价为 2 + 3 = 5 。现在 nums1 = [2,2,1,2,3] 。\n- 交换下标为 1 和 4 的两个值，代价为 1 + 4 = 5 。现在 nums1 = [2,3,1,2,2] 。\n总代价为 10 ，是所有方案中的最小代价。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>nums1 = [1,2,2], nums2 = [1,2,2]\n<b>输出：</b>-1\n<b>解释：</b>\n不管怎么操作，都无法满足题目要求。\n所以返回 -1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == nums1.length == nums2.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[i] &lt;= n</code></li>\n</ul>\n",
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